2) Invent a problem for which the solution is: (0.02 kg)(300 m/s) - (10 N) (0.4 m/s) = (0.02 kg) (100 m/s)

College Physics
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Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Invent a Problem for Which the Solution is:**

\[
(0.02 \, \text{kg})(300 \, \text{m/s}) - (10 \, \text{N})(0.4 \, \text{m/s}) = (0.02 \, \text{kg})(100 \, \text{m/s})
\]

**Instructions:**
Create a scenario that involves these values, explain the dynamics, and then illustrate this scenario with a sketch and a momentum bar chart. Consider the principles of momentum and force in your explanation.

---

For a sketch:
- Visualize the object with an initial speed (300 m/s).
- Show the application of a force (10 N) acting over a specific time or distance.
- Depict the object's final state with a reduced speed (100 m/s).

For a momentum bar chart:
- Represent initial momentum: \(0.02 \, \text{kg} \times 300 \, \text{m/s}\).
- Show the effect of force applied over time on the momentum.
- Illustrate the final momentum: \(0.02 \, \text{kg} \times 100 \, \text{m/s}\).
Transcribed Image Text:**Invent a Problem for Which the Solution is:** \[ (0.02 \, \text{kg})(300 \, \text{m/s}) - (10 \, \text{N})(0.4 \, \text{m/s}) = (0.02 \, \text{kg})(100 \, \text{m/s}) \] **Instructions:** Create a scenario that involves these values, explain the dynamics, and then illustrate this scenario with a sketch and a momentum bar chart. Consider the principles of momentum and force in your explanation. --- For a sketch: - Visualize the object with an initial speed (300 m/s). - Show the application of a force (10 N) acting over a specific time or distance. - Depict the object's final state with a reduced speed (100 m/s). For a momentum bar chart: - Represent initial momentum: \(0.02 \, \text{kg} \times 300 \, \text{m/s}\). - Show the effect of force applied over time on the momentum. - Illustrate the final momentum: \(0.02 \, \text{kg} \times 100 \, \text{m/s}\).
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