2) In the space below, draw all of the stereoisomers of molecule a. a) CH 3 =0 H-C-F H-C-F F-C-H CH3

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Chapter1: Chemical Foundations
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**Question 2**: In the space below, draw all of the *stereoisomers* of molecule a.

**a)**

The diagram shows a vertical carbon chain consisting of four carbon atoms. Here is the structure from top to bottom:

1. The top carbon (C) is bonded to a methyl group (CH₃) and a chlorine atom (Cl).
2. The second carbon (C) has a hydrogen (H) on the left and a fluorine (F) on the right.
3. The third carbon (C) has a hydrogen (H) on the left and a fluorine (F) on the right.
4. The fourth carbon (C) is bonded to a fluorine (F) on the left and a hydrogen (H) on the right.
5. The bottom carbon (C) is bonded to a methyl group (CH₃).

This tetrahedral configuration around each carbon atom can lead to different stereoisomers due to the different spatial arrangements of groups, particularly around the chiral centers.
Transcribed Image Text:**Question 2**: In the space below, draw all of the *stereoisomers* of molecule a. **a)** The diagram shows a vertical carbon chain consisting of four carbon atoms. Here is the structure from top to bottom: 1. The top carbon (C) is bonded to a methyl group (CH₃) and a chlorine atom (Cl). 2. The second carbon (C) has a hydrogen (H) on the left and a fluorine (F) on the right. 3. The third carbon (C) has a hydrogen (H) on the left and a fluorine (F) on the right. 4. The fourth carbon (C) is bonded to a fluorine (F) on the left and a hydrogen (H) on the right. 5. The bottom carbon (C) is bonded to a methyl group (CH₃). This tetrahedral configuration around each carbon atom can lead to different stereoisomers due to the different spatial arrangements of groups, particularly around the chiral centers.
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