2) In an oil-gas turbine installation, air is taken at pressure of 1 bar and 27°C and compressed to a pressure of 4 bar. The oil with a calorific value of 42,000 kJ/kg is burnt in the combustion chamber to raise the temperature of air to 550°C. If the air flows at the rate of 1.2 kg/s; find the net power of the installation. Also find the air-fuel ratio. Take Cp =1.05 kJ/kg K. [Hint: Determine the mass of fuel burnt by dividing the heat supplied to air by the calorific value of fuel. Air-fuel ratio is the ratio of mass of air to the mass of fuel. Mass of fuel burnt per second = (Heat supplied to air/ Calorific value of fuel) Air-fuel ratio = (Mass of air/ Mass of fuel)]
2) In an oil-gas turbine installation, air is taken at pressure of 1 bar and 27°C and compressed to a pressure of 4 bar. The oil with a calorific value of 42,000 kJ/kg is burnt in the combustion chamber to raise the temperature of air to 550°C. If the air flows at the rate of 1.2 kg/s; find the net power of the installation. Also find the air-fuel ratio. Take Cp =1.05 kJ/kg K. [Hint: Determine the mass of fuel burnt by dividing the heat supplied to air by the calorific value of fuel. Air-fuel ratio is the ratio of mass of air to the mass of fuel. Mass of fuel burnt per second = (Heat supplied to air/ Calorific value of fuel) Air-fuel ratio = (Mass of air/ Mass of fuel)]
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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In an oil turbine installation , air is taken at pressure of 1 bar and and 27 C and compressed to a pressure of 4 bar., The oil with a calorific value of 42000kg..
Answer step by step . Do all calculation .Don,t miss any part.. answer follow image
![2) In an oil-gas turbine installation, air is taken at pressure of 1 bar and
27°C and compressed to a pressure of 4 bar. The oil with a calorific
value of 42,000 kJ/kg is burnt in the combustion chamber to raise
the temperature of air to 550°C. If the air flows at the rate of 1.2
kg/s; find the net power of the installation. Also find the air-fuel
ratio. Take Cp = 1.05 kJ/kg K.
[Hint: Determine the mass of fuel burnt by dividing the heat supplied to air by the
calorific value of fuel. Air-fuel ratio is the ratio of mass of air to the mass of fuel.
Mass of fuel burnt per second = (Heat supplied to air/ Calorific value of fuel)
Air-fuel ratio = (Mass of air/ Mass of fuel)]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Feceb973c-efbf-41b1-9352-517bbed7f535%2F738aaac8-b4f6-4d3a-81a8-68ca4f485c2e%2Ffe2ss4n_processed.png&w=3840&q=75)
Transcribed Image Text:2) In an oil-gas turbine installation, air is taken at pressure of 1 bar and
27°C and compressed to a pressure of 4 bar. The oil with a calorific
value of 42,000 kJ/kg is burnt in the combustion chamber to raise
the temperature of air to 550°C. If the air flows at the rate of 1.2
kg/s; find the net power of the installation. Also find the air-fuel
ratio. Take Cp = 1.05 kJ/kg K.
[Hint: Determine the mass of fuel burnt by dividing the heat supplied to air by the
calorific value of fuel. Air-fuel ratio is the ratio of mass of air to the mass of fuel.
Mass of fuel burnt per second = (Heat supplied to air/ Calorific value of fuel)
Air-fuel ratio = (Mass of air/ Mass of fuel)]
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