2) If iron(II) sulfate is heated too strongly, the following reaction will occur FeSO4(s) FeO(s) + SO3(g) If you are heating a sample of FeSO4 6H2O and this reaction occurs along with dehydration, what will happen to the experimental percent water? Explain your answer. visynon tro

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**Text Transcription for Educational Website**

### Reactions and Calculations with Hydrates

**1. Aluminum Chloride Hexahydrate**

\[ \text{Aluminum Chloride Hexahydrate: } \text{AlCl}_3 \cdot 6\text{H}_2\text{O} \]

- **AlCl₃ Molecular Weight:** 133.34 g/mol
- **AlCl₃·6H₂O Molecular Weight Calculation:** 
  \[ 133.34 + 6(18.02) = 241.46 \, \text{g/mol} \]

- **Percentage of Water (Th\%):**
  \[
  \text{Th\%} = \left( \frac{6(18.02)}{241.46} \right) \times 100\% = 44.78\%
  \]

**2. Reaction of Iron(II) Sulfate**

- **Reaction:** 
  \[ \text{FeSO}_4(s) \rightarrow \text{FeO}(s) + \text{SO}_3(g) \]

- If you heat a sample of FeSO₄·6H₂O and this reaction occurs along with dehydration, the experimental percent water will likely decrease since SO₃ is released as a gas, indicating additional weight loss beyond water alone.

**3. Determining Water Content in Calcium Chloride Hydrate**

- **Given:** 8.416 g sample of CaCl₂·xH₂O; 5.624 g remains after heating.
- **Mass of H₂O lost:** 
  \[ 8.416 \, \text{g} - 5.624 \, \text{g} = 2.792 \, \text{g} \]

- **Moles of H₂O:**
  \[ 2.792 \, \text{g} \times \left( \frac{1 \, \text{mol}}{18.02 \, \text{g}} \right) = 0.1549 \, \text{mol} \]

- **Moles of CaCl₂:**
  \[ 5.624 \, \text{g} \times \left( \frac{1 \, \text{mol}}{110.98 \, \text{
Transcribed Image Text:**Text Transcription for Educational Website** ### Reactions and Calculations with Hydrates **1. Aluminum Chloride Hexahydrate** \[ \text{Aluminum Chloride Hexahydrate: } \text{AlCl}_3 \cdot 6\text{H}_2\text{O} \] - **AlCl₃ Molecular Weight:** 133.34 g/mol - **AlCl₃·6H₂O Molecular Weight Calculation:** \[ 133.34 + 6(18.02) = 241.46 \, \text{g/mol} \] - **Percentage of Water (Th\%):** \[ \text{Th\%} = \left( \frac{6(18.02)}{241.46} \right) \times 100\% = 44.78\% \] **2. Reaction of Iron(II) Sulfate** - **Reaction:** \[ \text{FeSO}_4(s) \rightarrow \text{FeO}(s) + \text{SO}_3(g) \] - If you heat a sample of FeSO₄·6H₂O and this reaction occurs along with dehydration, the experimental percent water will likely decrease since SO₃ is released as a gas, indicating additional weight loss beyond water alone. **3. Determining Water Content in Calcium Chloride Hydrate** - **Given:** 8.416 g sample of CaCl₂·xH₂O; 5.624 g remains after heating. - **Mass of H₂O lost:** \[ 8.416 \, \text{g} - 5.624 \, \text{g} = 2.792 \, \text{g} \] - **Moles of H₂O:** \[ 2.792 \, \text{g} \times \left( \frac{1 \, \text{mol}}{18.02 \, \text{g}} \right) = 0.1549 \, \text{mol} \] - **Moles of CaCl₂:** \[ 5.624 \, \text{g} \times \left( \frac{1 \, \text{mol}}{110.98 \, \text{
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