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2 east one of the answers above is NOT correct. e ite the given third order linear equation as an equivalent system of first order equations with initial values. S4y" - t²y + (2t²+3) y = −2t \y(3) = 3, y'(3) = 2, Y2 = y', and 0 1898-8 0 0 Y + 0 Y₁ = Y, 0 = y". Y3 = 0 0 2 -2t correct y" (3) = 2

2 east one of the answers above is NOT correct. e ite the given third order linear equation as an equivalent system of first order equations with initial values. S4y" - t²y + (2t²+3) y = −2t \y(3) = 3, y'(3) = 2, Y2 = y', and 0 1898-8 0 0 Y + 0 Y₁ = Y, 0 = y". Y3 = 0 0 2 -2t correct y" (3) = 2

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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1 t^2 Use 0 Y' = 0 O -2*t 3 3 2 At least one of the answers above is NOT correct. 2 = Y2 = y', and 0 0 --1888-181 0 0 Y + 0 with initial values Y 3 = 3 2 Y3 = = y". 0 0 -2t 1 If you don't get this in 3 tries, you can get a hint. t² 0 0 0 - 2t 3 3 Write the given third order linear equation as an equivalent system of first order equations with initial values. S4y" - t²y + (2t2² + 3) y = − 2t \g(3) = 3, y' (3) = 2, y" (3) = 2 2 2 incorrect incorrect correct correct correct incorrect correct correct correct correct
Transcribed Image Text:1 t^2 Use 0 Y' = 0 O -2*t 3 3 2 At least one of the answers above is NOT correct. 2 = Y2 = y', and 0 0 --1888-181 0 0 Y + 0 with initial values Y 3 = 3 2 Y3 = = y". 0 0 -2t 1 If you don't get this in 3 tries, you can get a hint. t² 0 0 0 - 2t 3 3 Write the given third order linear equation as an equivalent system of first order equations with initial values. S4y" - t²y + (2t2² + 3) y = − 2t \g(3) = 3, y' (3) = 2, y" (3) = 2 2 2 incorrect incorrect correct correct correct incorrect correct correct correct correct
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