2 C2H6 (g) + 7 O2 (g) -> 4 CO2 (g) + 6 H2O  ∆H° = – 3119 kJ molrxn–1 C2H4 (g) + 3 O2 (g) -> 2 CO2 (g) + 2 H2O      ∆H°= – 1411 kJ molrxn–1 2 H2 (g) + O2 (g) -> 2 H2O                                ∆H° = – 572 kJ molrxn–1 Use the information above to find the ∆H°rxn for the formation of ethene from ethane.

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One of the steps in the manufacturing of the plastic polyethylene is to remove H2 from C2H6 (ethane) to produce
C2H4 (ethene), utilizing the reaction below.

C2H6 (g) -> C2H4 (g) + H2 (g) ∆H°rxn = ?


From other experiments conducted, the following thermochemical equations are known.


2 C2H6 (g) + 7 O2 (g) -> 4 CO2 (g) + 6 H2O  ∆H° = – 3119 kJ molrxn–1
C2H4 (g) + 3 O2 (g) -> 2 CO2 (g) + 2 H2O      ∆H°= – 1411 kJ molrxn–1
2 H2 (g) + O2 (g) -> 2 H2O                                ∆H° = – 572 kJ molrxn–1


Use the information above to find the ∆H°rxn for the formation of ethene from ethane.

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