Given the following thermochemical equations, Equation 1: 4B(s) + 302(g) – 2B203(s) Equation 2: H2 (g) + % 02(g) → H20 (g) AHO= -2543.8 kJ AHO= -241.8 kJ Equation 3: B2H6(s) + 302(g) → B203(s) + 3H20 (g) AHO= -2032.9 kJ Which of the following statement's is/are true in calculating the AHO for the decomposition of B2H6 into its elements? Check all that apply. O Equation 1 was reversed and divided by 1/2. Equation 2 was reversed and multiplied by 3. O Equation 1 was reveresed and divided by 2. O Equation 3 was neither reversed nor multiplied by a factor.

Given the following thermochemical equations, Equation 1: 4B(s) + 302(g) – 2B203(s) Equation 2: H2 (g) + % 02(g) → H20 (g) AHO= -2543.8 kJ AHO= -241.8 kJ Equation 3: B2H6(s) + 302(g) → B203(s) + 3H20 (g) AHO= -2032.9 kJ Which of the following statement's is/are true in calculating the AHO for the decomposition of B2H6 into its elements? Check all that apply. O Equation 1 was reversed and divided by 1/2. Equation 2 was reversed and multiplied by 3. O Equation 1 was reveresed and divided by 2. O Equation 3 was neither reversed nor multiplied by a factor.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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