(2) C mass percent of acetic acid in the vinegar sample. You may want to brealk the calculation down to the following steps: Using the volume and molarity of NaOH, find the number of moles of NaOH that were used in this titration. Use this to get the number of moles of acetic acid in the vinegar sample that was titrated. Convert moles of acetic acid to grams of acetic acid for the vinegar sample that was titrated. To do this, you will need acetic acid's molar mass. (Note: HOAc is NOT the formula, the actual formula is HC2H302.) After converting grams to moles, you now have the mass of acetic acid in the vinegar sample. o Now find the mass of the entire vinegar sample that was titrated. You may do this by assuming that the density of the vinegar solution is 1.02 g/mL Finally, find the percent acetic acid in the vinegar sample. .
(2) C mass percent of acetic acid in the vinegar sample. You may want to brealk the calculation down to the following steps: Using the volume and molarity of NaOH, find the number of moles of NaOH that were used in this titration. Use this to get the number of moles of acetic acid in the vinegar sample that was titrated. Convert moles of acetic acid to grams of acetic acid for the vinegar sample that was titrated. To do this, you will need acetic acid's molar mass. (Note: HOAc is NOT the formula, the actual formula is HC2H302.) After converting grams to moles, you now have the mass of acetic acid in the vinegar sample. o Now find the mass of the entire vinegar sample that was titrated. You may do this by assuming that the density of the vinegar solution is 1.02 g/mL Finally, find the percent acetic acid in the vinegar sample. .
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Part 1 calculations
Number of grand of potassium hydrogen phthalate = 0.55227g
moles of KHP = 204.2
moles of NaOH = 0.00270
molarity of NaOH = 0.105
part 2
initial volume 0.2ml
final volume 40.2 ml
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