2) Applications of gas laws to atmospheric science. Atmospheric pollution is a problem that has received much attention. Not all pollution is from industrial sources. Volcanic eruptions can be a significant source of air pollution. The Kilauea volcano in Hawaii emits between 300 and 400 metric ton (t) of SO₂ per day. If this gas is emitted at 800°C and 1.0 atm, what volume of gas is emitted? Hint: since both the lower limit of 300 t and the upper limit of 400 t are provided, give answers for both amounts. Hint: since the temperature is quite high, assume ideal gas behavior.

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Application of gas laws to atmospheric science
Applications of gas laws to atmospheric science.
Atmospheric pollution is a problem that has received much attention. Not all pollution is from
industrial sources. Volcanic eruptions can be a significant source of air pollution.
The Kilauea volcano in Hawaii emits between 300 and 400 metric ton (t) of SO₂ per day.
2)
If this gas is emitted at 800°C and 1.0 atm, what volume of gas is emitted?
Hint: since both the lower limit of 300 t and the upper limit of 400 t are provided, give answers
for both amounts.
Hint: since the temperature is quite high, assume ideal gas
behavior.
Transcribed Image Text:Applications of gas laws to atmospheric science. Atmospheric pollution is a problem that has received much attention. Not all pollution is from industrial sources. Volcanic eruptions can be a significant source of air pollution. The Kilauea volcano in Hawaii emits between 300 and 400 metric ton (t) of SO₂ per day. 2) If this gas is emitted at 800°C and 1.0 atm, what volume of gas is emitted? Hint: since both the lower limit of 300 t and the upper limit of 400 t are provided, give answers for both amounts. Hint: since the temperature is quite high, assume ideal gas behavior.
Expert Solution
Step 1

Given,

Lower limit :

Mass of gas emitted = 300 metric ton 

And 1 metric ton = 1000000 g so the mass of gas emitted = 300000000 g

T = 800 degree Celsius = 800 + 273 K = 1073 K

And P = 1.0 atm 

And the molar mass of Sulfur oxide = 64.0 g/mol

So Number of moles = 300000000g64 g/mol = 4.69 × 106 moles

 

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