2) Application of the polygon-and-circle technique (Frost circle) reveals that single electrons occupy each of the two nonbonding orbitals in the molecular orbital diagram of: A) Cyclobutadiene B) Benzene C) Cyclopropenyl cation D) Cyclopentadienyl anion

2) Application of the polygon-and-circle technique (Frost circle) reveals that single electrons occupy each of the two nonbonding orbitals in the molecular orbital diagram of: A) Cyclobutadiene B) Benzene C) Cyclopropenyl cation D) Cyclopentadienyl anion

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter18: Aromaticity

Section: Chapter Questions

Problem 26CTQ

See similar textbooks

Similar questions

The structure of 1,2-propadiene (allene) is shown to the right. (a) Predict all approximate bond angles in this molecule. (b) State the orbital hybridization of each carbon. (c) Explain the three-dimensional geometry of allene in terms of the orbitals used.
(a)The concept of hybridization was first proposed by Linus Pauling in 1931, that explain about the concept of mixing orbitals to form new hybrid orbital suitable for the pairing of electrons to form chemical bonds. Draw the kekule structure of a compound that contains only carbon and hydrogen atoms that has: (1) One sp hybridize carbon, two sp? hybridized carbons and two sp hybridized carbon (ii) Two sp' hybridized carbon and two sp hybridized carbons (ii) Two sp? hybidized carbons and two sp hybydized carbon
The unsaturation number or degree of unsaturation (U) can be used to determine the number of rings and multiple bonds in a compound from its molecular formula. Given a structure, you can determine the number of hydrogens without having to count them explicitly. Consider three compounds and their degree of unsaturation. (a) A compound A has the molecular formula C7H13ClN2OC7⁢H13⁢ClN2O. How many rings and/or π bonds does it contain?
Section 7.3 shows that the compound 2-butene exists intwo isomeric forms, which can be interconverted only bybreaking a bond (in that case, the central double bond).How many possible isomers correspond to each of the following chemical formulas? Remember that a simple rotation of an entire molecule does not give a different isomer.Each molecule contains a central CuC bond.(a) C2H2Br2(b) C2H2BrCl(c) C2HBrClF
Investigation has shown that cyclobutadiene is actually a rectangular molecule rather than a square molecule. Explain the reason for this observation.
4. Octatetraene, C8H10, is an 8-membered linear carbon chain with alternating single and double bonds. As a result, each carbon is left with an unhybridized p-orbital containing one electron. This problem will take you through steps to construct and fill the molecular orbital diagram for octatetraene based on the way these different p-orbitals can come together. a) The various molecular orbitals formed from octatetraene’s 8 unhybridized p-orbitals are shown on the next page. Draw the nodal planes for each molecular orbital. Hint: A nodal plane is a line through the molecule that denotes the sites of destructive interference. An example is shown below with ethylene. b) Based on the nodal planes, arrange the energy levels corresponding to the 8 molecular orbitals on the energy level diagram (label them using the numbering provided on the left side of the molecular orbitals) on the next page, in order of lowest to highest energy. c) Populate your molecular…
he structure of 1,2-propadiene (allene) is shown to the right. Q.)Explain the three-dimensional geometry of allene in terms of the orbitals used
sketch and label the orbitals in ethene according to valence bond theory?
Draw the molecular orbital diagram of buta-1.3-diene.
The longest wavelength electronic transition in simple unsaturated hydrocarbons corresponds to a transition from the highest occupied molecular orbita l (HOMO) to the lowest unoccupied molecular orbita l (LUMO) . Predict the energy of the HOMO to LUMO separation in (a) ethane. (b) butadiene. and (c) benzene.
Nn.49. Subject :- Chemistry
Square planar molecules with formula AB2C2 and octahedral molecules with formulas AB4C2 and AB3C3 feature diastereoisomers. Recall that trigonal bipyramidal geometry features two distinct positions: axial and equatorial. Draw all diastereoisomers for trigonal bipyramidal molecules with formula (a) AB4C and (b) AB3C2. You must indicate the stereochemistry using full and dashed wedges and label all positions as either axial (ax) and equatorial (eq)..