(2) An electron moving at a speed of v = 0.960c in the positive x direction collides with anotherelectron at rest. After the collision, one electron is observed to move with a speed v₁,f =0.956c at an angle of 0₁ = 9.7° with the x axis.(a) Use conservation of energy to find the speed v2 of the second electron(b) Use conservation of momentum to find the direction 02 of the second electron.Note: Momentum is separately conserved in the x and y directions. Since you already knowv2 you only need to conserve momentum along one direction to fix 02.

Answered: Image /qna-images/answer/facf1523-967a-46cf-a23e-da523cc5710c.jpg

Answered: (2) An electron moving at a speed of v…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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An unstable particle with a mass equal to 3.34 ✕ 10−27 kg is initially at rest. The particle decays into two fragments that fly off with velocities of 0.981c and −0.861c, respectively. Find the masses of the fragments in kg. (Hint: Conserve both mass–energy and momentum.)
An electron has a momentum of 2.00 x 10-2¹ kg⋅m/s. Find the kinetic energy of the electron in units of MeV. (A) 2.31 (B) 5.74 (C) 4.97 (D) 3.27 (E) 6.49
The muon is an unstable subatomic particle witha mean lifetime of 2.2 μs, and about 10,000 muons reach everysquare meter of the earth's surface a minute. A muon has a linear momentum G, and after some short time it decays into two other elementary particles with masses m1 and m2. The energy Q released during the decay is converted entirely into the kinetic energy of the decay products (i.e., into kinetic energy of m1 and m2). Find linear momenta of decay products. Draw a vector diagram showing a range of momenta decay products can take.
An unstable particle is at rest and suddenly breaks up into two fragments. No external forces act on the particle or its fragments. One of the fragments has a velocity of +0.837c and a mass of 1.77 × 10-27 kg, and the other has a mass of 5.29 × 10-27 kg. What is the velocity of the more massive fragment (as a multiple of c)? (Hint: This problem is similar to Example 6 in Chapter 7.) Unstable particle at rest Number i V2 m2 Units m1 V1 Recoiling fragments
An unstable particle is at rest and suddenly breaks up into two fragments. No external forces act on the particle or its fragments. One of the fragments has a velocity of +0.811c and a mass of 1.57 × 10-27 kg, and the other has a mass of 5.98 × 10-27 kg. What is the velocity of the more massive fragment (as a multiple of c)? (Hint: This problem is similar to Example 6 in Chapter 7.) Unstable particle at rest V2 m2 m1 V1 Recoiling fragments
12. (a) A particle is traveling through the Earth's atmosphere at a speed of 0.750c. To an earth bound observer, the distance it travels is 2.5km. How far does the particle travel in the particle's frame of reference? (b) Calculate the momentum of an electron traveling at a speed 0.985c? The rest mass of the electron is 9.11 X 10-31 kg.
Particle A has a rest energy of 1192 MeV and is moving through the laboratory in the positive x direction with a speed of 0.450c. It decays into particle B (rest energy = 1116 MeV) and a photon; particle A disappears in the decay process. Particle B moves at a speed of 0.400c at an angle of 3.03° with the positive x axis. The photon moves in a direction at an angle with the positive x axis. A 0.45c What are the 0.40c photon Ө 3.03⁰ B in MeVs and your answer in three significant digits. in degrees of the photon? Give
1. (15 pts) A moving hydrogen atom (rest mass 939 MeV/c2, wherec is the speed of light in vacuum) has a kinetic energy of 313 MeV. (a) What is the total energy of this atom in MeV? (b) What is this particle's speed in terms of c? (c) What is the magnitude of this atom's linear momentum? 24 MacBook Air
Consider a proton that has a momentum of 1.00 kg·m/s. Part (a) Calculate the relativistic parameter γ for the proton. You will have to use a 2.998 × 108 for the speed of light to get this answer correct. Part (b) What is its speed, in meters per second? Such protons form a rare component of cosmic radiation with uncertain origins.
In a collider two protons are accelerated until they have kinetic energies of 1000 MeV (as seen in the lab). The pair is then split and brought around circular paths so that they are directed at each other. What speed of approach would one proton see the other as having? The mass of a proton is 1.673x10-27 kg (or 1.007276 u), and the rest mass energy of a proton is 938.3 MeV. (Speed is a scalar, so your answer will not need a direction.) K= 1000 MeV K = 1000 MeV
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Astrophysics 14 Use Newton's second law, F = dp/dt, and the formula for relativistic momentum, Eq. ( 44), to show that the acceleration vector a = dv/dt produced by a force F acting on a particle of mass m is F (F. v), ymc² Ym where F· v is the vector dot product between the force F and the particle velocity v. Thus the acceleration depends on the particle's velocity and is not in general in the same direction as the force. mv p = /1 – v²/c² = ymv (44) VI -

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