2 An article reported the results of a study to determine whether treadmill exercise could improve the walking ability of patients suffering from claudication, which is pain caused by insufficient blood flow to the muscles of the legs. A sample of 44.00 patients walked on a treadmill for 6 minutes every day. After 6 months, the mean distance walked in 6 minutes was 348 m, with a standard deviation of 80 m. For a control group of 42.00 patients who did not walk on a treadmill, the mean distance was 309 m with a standard deviation of 89 m. Can you conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls? Use the a = 0.05 level of significance. Find the P-value and state a conclusion. (Round the final answer to four decimal places.) The P-value is 0.0172 x We cannot conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls.
2 An article reported the results of a study to determine whether treadmill exercise could improve the walking ability of patients suffering from claudication, which is pain caused by insufficient blood flow to the muscles of the legs. A sample of 44.00 patients walked on a treadmill for 6 minutes every day. After 6 months, the mean distance walked in 6 minutes was 348 m, with a standard deviation of 80 m. For a control group of 42.00 patients who did not walk on a treadmill, the mean distance was 309 m with a standard deviation of 89 m. Can you conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls? Use the a = 0.05 level of significance. Find the P-value and state a conclusion. (Round the final answer to four decimal places.) The P-value is 0.0172 x We cannot conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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
Transcribed Image Text:2
An article reported the results of a study to determine whether treadmill exercise could improve the walking ability of patients suffering
from claudication, which is pain caused by insufficient blood flow to the muscles of the legs. A sample of 44.00 patients walked on a
treadmill for 6 minutes every day. After 6 months, the mean distance walked in 6 minutes was 348 m, with a standard deviation of 80
m. For a control group of 42.00 patients who did not walk on a treadmill, the mean distance was 309 m with a standard deviation of 89
m. Can you conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls? Use the a
= 0.05 level of significance. Find the P-value and state a conclusion. (Round the final answer to four decimal places.)
The P-value is 0.0172 x
We cannot conclude that the mean distance walked for patients using a treadmill is greater than the mean for the controls.
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