**Problem:** After doubling all of the scores, the mean was found to be 28 and the standard deviation was 4. What were the values for the mean and standard deviation (SD) before the change? Explain.**Solution:** To find the original mean and standard deviation before the scores were doubled, we can use the properties of mean and standard deviation with respect to scaling:1. **Mean:** - If all scores are doubled, the mean of the scores is also doubled. - Thus, if the doubled mean is 28, the original mean ($\mu$) is: \[ \mu = \frac{28}{2} = 14 \]2. **Standard Deviation:** - The standard deviation also scales linearly with multiplication. - If the doubled standard deviation is 4, the original standard deviation ($\sigma$) is: \[ \sigma = \frac{4}{2} = 2 \]Therefore, before doubling, the mean of the scores was 14 and the standard deviation was 2.

Let's denote the original mean as and the original standard deviation as .After doubling all of the…

Answered: 2) After doubling all of the scores,…

2) After doubling all of the scores, the mean was found to be 28 and the standard deviation was 4. What were the values for the mean and SD before the change? Explain

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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