2-A linear probing hash table of length 10 uses the hash function h(x) = x mod 10 + 1. mod is the reminder opertatro. For example the h(42) = 42 mod 10 + 1 = 2 + 1 = 3 so we insert 42 in t he position 3 in the array. After inserting 6 integer keys into an initially empty hash table, the array of keys is 1 2 3 4 7 8 9. 42 23 34 52 46 33 a- insert the key 35 b- insert the key 12 c- insert the key 10

2-A linear probing hash table of length 10 uses the hash function h(x) = x mod 10 + 1. mod is the reminder opertatro. For example the h(42) = 42 mod 10 + 1 = 2 + 1 = 3 so we insert 42 in t he position 3 in the array. After inserting 6 integer keys into an initially empty hash table, the array of keys is 1 2 3 4 7 8 9. 42 23 34 52 46 33 a- insert the key 35 b- insert the key 12 c- insert the key 10

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Modify the generic Pair.java class in two ways: Make it so that both values have the same type Add a method swap that swaps the first and second elements of the pair Examples:Pair<Integer> intPair = new Pair<>(17, 19);intPair.getFirst(); // returns 17intPair.getSecond(); // returns 19intPair.swap();intPair.getFirst(); // returns 19intPair.getSecond(); // returns 17Pair<String> strPair = new Pair<>("Erick", "Valdez");strPair.getFirst(); // returns "Erick"strPair.getSecond(); // returns "Valdez"strPair.swap();strPair.getFirst(); // returns "Valdez"strPair.getSecond(); // returns "Erick" Pair.java /*** This class collects a pair of elements of different types.*/public class Pair<T, S> {private T first;private S second;/*** Constructs a pair containing two given elements.* * @param firstElement the first element* @param secondElement the second element*/public Pair(T firstElement, S secondElement) {first = firstElement;second = secondElement;}/*** Gets…
Double Hashing Given input {19, 29, 7, 116, 44, 8, 45}, a hash function h(x) = x mod 11 and the double hash h2(key) = 7 - (key mod 7). Show the resulting hash table using double hashing. copyAndPaste the table into the textBox for your nice answer. Please consider showing work for the h(x). [0] [1] [2] [3] [4] [5] [6] [7] [8] [9] [10]
PYTHON Why am I getting an error and it doesn't show the right output? Problem 1# Implement a hashtable using an array. Your implementation should include public methods for insertion, deletion, and# search, as well as helper methods for resizing. The hash table is resized when the loadfactor becomes greater than 0.6# during insertion of a new item. You will be using linear probing technique for collision resolution. Assume the key to# be an integer and use the hash function h(k) = k mod m where m is the size of the hashtable. class HashTableProb: def __init__(self, size=10): # Initialize the hashtable with the given size and an empty array to hold the key-value pairs. self.__size = size # size of the hashtable self.__hashtable = [None for _ in range(size)] self.__itemcount = 0 # Keeps track of the number of items in the current hashtable def __contains__(self, key): return self.__searchkey(key) def __next_prime(self, x): def…
I am trying to implement a hash table of key-value pairs, where the key determines the location of the pair in the hash table, the key is what the hash function is used on. The hash table that I am trying to implement will use separate chaining (with unordered linked lists) for collision resolution. I need help changing the code where: 1. The "search" method of the code returns the node that was found or "None" 2. The "Node" implementation has a "key" and "value" member This is what I have so far class Node: def __init__(self,initdata): self.data = initdata self.next = None def getData(self): return self.data def getNext(self): return self.next def setData(self,newdata): self.data = newdata def setNext(self,newnext): self.next = newnext class UnorderedList: def __init__(self): self.head = None def isEmpty(self): return self.head == None def add(self,item): temp = Node(item) temp.setNext(self.head)…
Due to the poor design of our hashmap, all of the keys and values are stored in the same place (a LinkedList). This eliminates one of the main advantages of using a hash map.
Given array A = [514, 650, 174, 559, 649, 155, 200, 255, 520, 380]. Do the following tasks. a. Create an auxiliary array AUX. Use the hash function hash(element) to help yourself. Element refers to the elements in array A. def hash (element) : index = summation of each digit of (element 8 100) 810 return index [Don't write code for part a. You have to draw and show calculations if there are any] b. Complete the function find(A, AUX, key) that returns the frequency [number of times found] if key is found in A else return -1
Likewise, the get function begins by computing the initial hash value. If the value is not in the initial slot, rehash is used to locate the next possible position. Notice that line 15 guarantees that the search will terminate by checking to make sure that we have not returned to the initial slot. If that happens, we have exhausted all possible slots and the item must not be present. The final methods of the HashTable class provide additional dictionary functionality. We overload thegetitem_ and_setitem methods to allow access using "(1." This means that once a HashTable has been created, the familiar index operator will be available.
Our hash map data are all saved in a single LinkedList because of the shoddy way the map was built. The hash map's utility is reduced as a consequence.
All of the data in our hash map are kept in one bucket (a LinkedList) since the map was badly built. The benefits of a hash map are undermined by this.
Question 13 sum.Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
Write a method called inversePrint. This method gets a head of a linkedlist and Recursively print from the last item to the first one. This is a Recursive method. If Recursive is not used you will get no mark for this question Do not reverse the linkedlist, only print it in reverse example call: in the main I will call your method like: buffer = myList.head; //This is a buffer to copy the head address inversePrint(buffer); After this, the order for myList should not changed. if myList has: 1->2->3->4->5 your function should print: 5-> 4 -> 3->2->1 but if I check myList the order should still be 1->2->3->4->5 you can assume the LinkedList code for all other operations exist and if you need you can use them Do Not create a new linkedlist in inverse Hint: use recursion does this for you really easy
Find 2N strings, each of length 2N, that have the same hashCode() value, supposing that the hashCode() implementation for String is the following:public int hashCode(){ int hash = 0; for (int i = 0; i < length(); i ++) hash = (hash * 31) + charAt(i); return hash;}Strong hint : Aa and BB have the same value