(c)Q.2(a) (i) Briefly explain TWO major power losses in a power transformer.(ii) Suggest one method to reduce each power losses in Q.2(a)(i).(b) A single-phase transformer, 30 kVA, 1000 V/ 415 V, 50 Hz has the followingtest results:Open-circuit test: 1000 V, 1 A, 800 W (measured at the high voltage side)Short-circuit test: 120 V, 20 A, 1200 W (measured at the high voltage side)(i) By referring all parameters to the high voltage side, calculate the equivalentwinding resistance Reqi, equivalent winding reactance Xeql, the coreinternal resistance, R. and magnetizing reactance, Xm value.(ii) A full load with a 0.9 lagging power factor is connected to the transformer.Calculate the transformer's voltage regulation and efficiency.(iii) Determine the transformer's maximum efficiency when the load is at 0.9power factor lagging.Figure Q.2(c) shows the Y-A configuration of a three-phase power transformer.Give two reasons why this configuration is preferred as a step-up transformer.bFigure Q.2(c)b

Since you have posted the multiple questions with multiple support. so we are supposed to answer 1st…

2 (a) (i) Briefly explain TWO major power losses in a power (ii) Suggest one method to reduce each power losses in Q.2(a)(i). (b) A single-phase transformer, 30 kVA, 1000 V/ 415 V, 50 Hz has the following test results: side)

2 (a) (i) Briefly explain TWO major power losses in a power (ii) Suggest one method to reduce each power losses in Q.2(a)(i). (b) A single-phase transformer, 30 kVA, 1000 V/ 415 V, 50 Hz has the following test results: side)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Consider the three single-phase two-winding transformers shown in Figure. 3. The high-voltage windings are connected in Y. (a) For the low-voltage side, connect the windings in A, and label the terminals a, b, and c in accordance with the American standard. (b) Relabel the terminals a', b', and c' such that VAN is 90° out of phase with V₂'b' for positive sequence. DI H₂ Figure. 3: Three-Winding Transformer
Example 1: A single-phase, 100-kVA, 1000:100-V, 60-Hz transformer has the following test results: Open-circuit test (HV side open): 100 V, 6 A, 400 W Short-circuit test (LV side shorted): 50 V, 100 A, 1800 W 1. Draw equivalent circuit of the transformer referred to the high-voltage side. Label impedances numerically in ohms and in per unit. 2. Determine the voltage regulation at rated secondary current with 0.6 power factor lagging. Assume the primary is supplied with rated voltage 3. Determine the efficiency of the transformer when the secondary current is 75% of its rated value and the power factor at the load is 0.8 lagging with a secondary voltage of 98 V across the load
Sen 2.5 2.5 A 16,25 kVA, 220/440 V, 60 Hz transformer gave the following test results. Open circuit test (440 V side open): 220 V, 9.5 A, 650 W Short-circuit test (220 V side shorted): 37.5 V, 55 A, 950 W (a) Derive the approximate equivalent circuit in per-unit values. (b) Determine the voltage regulation at full load, 0.8 PF lagging. (c) Draw the phasor diagram for condition (b).
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Construct the circuit in Figure 1 in the Circuit JS simulator. Note that the voltage source is given in RMS. Within Circuit JS while defining the max voltage of the voltage source include “rms” after the number to tell Circuit JS that this is a rms value. Also note that there are additional parameters when instantiating a transformer in Circuit JS. Leave these at the default values. Additionally, transformers may have problems simulating in Circuit JS. Answer the following: 1. From the simulation results, determine the power dissipated in R2 and compare to the expected value from the previous section.2. Change the transformer ratio (“Ratio” as a fraction when you “Edit…” the transformer component) to the value calculated in the previous section to provide maximum power transfer in R2. Note: In Circuit JS, Transformer Ratio = Primary/Secondary.3. Rerun the simulation, calculate the power dissipated in R2 and compare to the expected value from the previous section.4. Change the…
Derive the mutual-inductance of 2-winding IT in terms of the physical parameters of the transformer.
QUESTIONS: 1. A 10 kVA, single-phase, 2400-V:120-V, 60 Hz transformer has an equivalent impedance referred to LV side of 0.01 + j0.09 Q. This transformer has a core loss of 100 W at rated voltage. When rated current is applied to the 2400-V winding, the exciting current in that winding is found to be 0.2 A. a. Find the full-load regulation of this transformer at a power factor of 0.8 lagging. b. Find the efficiency of this transformer at full load, 0.8 power factor lagging. c. Ifstandard open-circuit and tests were performed on this transformer, what would be the measured values of these tests? 2. The following data were obtained on a 2.5 MVA, 50-Hz, 19.1-kV:3.81-kV single-phase transformer tested at 50 Hz: Voltage (V) Current (A) Power (kW) LV winding with HV terminals open-circuited: 3810 9.86 8.14 HV winding with LV terminals short-circuited: 920 141 10.3 a. Calculate the cantilever equivalent-circuit parameters as referred to the transformer high-voltage winding. b. Calculate the…
Electrical Machines 3.1...
A 36/240 V phase transformer, belonging to a phase measured from the no-load (idle) run and short-circuit test. values are given in the table below. High voltage by applying rated voltage to the low voltage winding (The winding ends were left unloaded and the results of the no-load test results were obtained. By applying nominal current to the high voltage windings, the low voltage windings were short-circuited, and the results of the short circuit test were obtained. In direct current test 1 V direct voltage is applied to the low voltage winding, and the transformer draws 500 A direct current. All equivalent Calculate the circuit elements as moved to the low voltage side. Idle run test: Voltage : 36V Power : 68W Current : 2,8A Short circuit test: Voltage : 15V Power : 325W Current : 42,2A
High voltage engineering
Y=3