2) A cyanide ion selective electrode obeys the equation : E (volts) = constant - 0.05916 log [CN-] The measured potential was - 0.224 V when immersed in 0.00100 M NaCN. a) What is the value of the numerical constant from the calibration equation? -0.402 b) Using (a), what is the [CN] in a solution with an E= -0.286 V ?

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### Cyanide Ion Selective Electrode Calibration

**Equation and Conditions:**

A cyanide ion selective electrode obeys the equation:

\[ E (\text{volts}) = \text{constant} - 0.05916 \log [\text{CN}^-] \]

The measured potential was **-0.224 V** when immersed in **0.00100 M NaCN**.

**Questions:**

a) **Determine the Numerical Constant:**

   Calculate the value of the numerical constant from the calibration equation.

   - Answer: \(-0.40\)

b) **Calculate \([\text{CN}^-]\):**

   Using the constant from part (a), determine the \([\text{CN}^-]\) in a solution with a potential of **E = -0.286 V**.
Transcribed Image Text:### Cyanide Ion Selective Electrode Calibration **Equation and Conditions:** A cyanide ion selective electrode obeys the equation: \[ E (\text{volts}) = \text{constant} - 0.05916 \log [\text{CN}^-] \] The measured potential was **-0.224 V** when immersed in **0.00100 M NaCN**. **Questions:** a) **Determine the Numerical Constant:** Calculate the value of the numerical constant from the calibration equation. - Answer: \(-0.40\) b) **Calculate \([\text{CN}^-]\):** Using the constant from part (a), determine the \([\text{CN}^-]\) in a solution with a potential of **E = -0.286 V**.
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