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(2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!

(2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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(2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!
Transcribed Image Text:(2) A CHEM 215 student performed 5 measurements of the wt% of SO4²- of a solid power sample. The results are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%. The standard deviation is 0.10%. What is the confidence interval for this student's experiment at 95% confidence level. The t values for 95% confidence for degree of freedom from 1 to 5 are 12.71, 4.303, 3.182, 2.776, 2.571, respectively. Show your work!
Expert Solution
Step 1: Interpretation of problem statement

Given Data: 

The result of an experiment performed by a student :

5 measurements of the wt% of SO42- are 8.75%, 8.85%, 8.89%, 8.71%, 8.64%

Standard deviation = 0.10 %

To determine:

Confidence interval for student's experiment at 95% Confidence interval

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