2 A 0.5 h.p., 230V, single-phase induction motor (split-phase) takes a current of 4.2A lagging the voltage by 10° for the starting winding and a current of 6.2A lagging the voltage by 40° for its main winding. Find (i) total current and power factor at the time of starting (ii) total current and power factor during running (iii) phase angle between the main winding current and starting winding current (iv) power drawn by starting winding (v) power drawn by main
2 A 0.5 h.p., 230V, single-phase induction motor (split-phase) takes a current of 4.2A lagging the voltage by 10° for the starting winding and a current of 6.2A lagging the voltage by 40° for its main winding. Find (i) total current and power factor at the time of starting (ii) total current and power factor during running (iii) phase angle between the main winding current and starting winding current (iv) power drawn by starting winding (v) power drawn by main
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter32: Three-phase Motors
Section: Chapter Questions
Problem 6RQ: Name three factors that determine the torque produced by an induction motor.
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![Q2
A 0.5 h.p., 230V, single-phase induction motor (split-phase) takes a current of 4.2A lagging the
voltage by 10° for the starting winding and a current of 6.2A lagging the voltage by 40° for its
main winding. Find (i) total current and power factor at the time of starting (ii) total current
and power factor during running (iii) phase angle between the main winding current and
starting winding current (iv) power drawn by starting winding (v) power drawn by main
winding (vi) total power drawn during starting (vii) total power drawn during running. Ans[
10.06 A, 0.883lag ,6.2A, 0.766lag, 30°, 951.32W, 1092.38W, 2043.7W, 1092.38W]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd99d685b-8f9a-42c0-8957-dd785aa9fd3d%2F3cac7c08-2061-47ad-bb3f-770ae8ec5faf%2F1k7ef5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q2
A 0.5 h.p., 230V, single-phase induction motor (split-phase) takes a current of 4.2A lagging the
voltage by 10° for the starting winding and a current of 6.2A lagging the voltage by 40° for its
main winding. Find (i) total current and power factor at the time of starting (ii) total current
and power factor during running (iii) phase angle between the main winding current and
starting winding current (iv) power drawn by starting winding (v) power drawn by main
winding (vi) total power drawn during starting (vii) total power drawn during running. Ans[
10.06 A, 0.883lag ,6.2A, 0.766lag, 30°, 951.32W, 1092.38W, 2043.7W, 1092.38W]
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