2 6. For the telescoping series find a formula for the nth term of the sequence of (2k + 3)(2k + 5)' k=1 partial sums {Sn}. Then, evaluate lim Sn to obtain the value of the series or state that the series diverges. 81x

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Chapter1: Functions And Models
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**Problem 6: Telescoping Series**

Given the telescoping series:

\[ \sum_{k=1}^{\infty} \frac{2}{(2k+3)(2k+5)} \]

1. **Find a formula for the \(n\)th term of the sequence of partial sums \(\{S_n\}\).**
2. **Evaluate \( \lim_{n \to \infty} S_n \) to obtain the value of the series or state that the series diverges.**

**Explanation:**

- A **telescoping series** is a series whose partial sums eventually only have a fixed number of terms after cancellation.
- The given expression is in the form of a fraction, and we aim to simplify and break it into more manageable components for summation.
- To achieve the solution, decompose the fraction and simplify the terms, observing the pattern in partial sums.

By solving this, you will be able to determine the behavior of the series as \(n\) approaches infinity and conclude if the series converges or diverges.
Transcribed Image Text:**Problem 6: Telescoping Series** Given the telescoping series: \[ \sum_{k=1}^{\infty} \frac{2}{(2k+3)(2k+5)} \] 1. **Find a formula for the \(n\)th term of the sequence of partial sums \(\{S_n\}\).** 2. **Evaluate \( \lim_{n \to \infty} S_n \) to obtain the value of the series or state that the series diverges.** **Explanation:** - A **telescoping series** is a series whose partial sums eventually only have a fixed number of terms after cancellation. - The given expression is in the form of a fraction, and we aim to simplify and break it into more manageable components for summation. - To achieve the solution, decompose the fraction and simplify the terms, observing the pattern in partial sums. By solving this, you will be able to determine the behavior of the series as \(n\) approaches infinity and conclude if the series converges or diverges.
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