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2-2. If e = 60° and T = 5 kN, determine the magnitude of the resultant force acting on the eyebolt and its direction measured clockwise from the positivex axis. 8 kN

2-2. If e = 60° and T = 5 kN, determine the magnitude of the resultant force acting on the eyebolt and its direction measured clockwise from the positivex axis. 8 kN

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2-2. If e = 60° and T = 5 kN, determine the magnitude of the resultant force acting on the eyebolt and its direction measured clockwise from the positive x axis. 8 kN The parallelogram law of addition and the triangular rule are shown in Figs. a and b, respectively. Applying the law of cosines to Fig. b, FR =52+82-2SX8)cos 105° = 10.47 kN = 10.5 kN %3D Ans. Applying the law of sines to Fig. band using this result, yields sina sin 105° a = 47.54° 8 10.47 Thus, the direction angle o of FR measured clockwise from the positive xaxis is O =a - 30° =47.54°-30° 17.5° Ans. 5 KN -60%45의105° 600 5KN 10s 8 KN 450 FR (b) 8 kN (a)
Transcribed Image Text:2-2. If e = 60° and T = 5 kN, determine the magnitude of the resultant force acting on the eyebolt and its direction measured clockwise from the positive x axis. 8 kN The parallelogram law of addition and the triangular rule are shown in Figs. a and b, respectively. Applying the law of cosines to Fig. b, FR =52+82-2SX8)cos 105° = 10.47 kN = 10.5 kN %3D Ans. Applying the law of sines to Fig. band using this result, yields sina sin 105° a = 47.54° 8 10.47 Thus, the direction angle o of FR measured clockwise from the positive xaxis is O =a - 30° =47.54°-30° 17.5° Ans. 5 KN -60%45의105° 600 5KN 10s 8 KN 450 FR (b) 8 kN (a)
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