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(2 2" (2"-1)a - 3 If A = then A" = Éro* +1) = -m(n + 1)(a° +n+2) 4 5 Ertr-1)=,n(n² - 1(3n + 2) 12 Given that y =xe", then d"y = (x +n)e*. dx" 6. 1x2 2x3 3x 4 n(n+1) n+1 n'-n is divisible by 6. E (4r - 3) =m(n+1)X2n² – 1). 10 (1x2)+(2+(3x 4)+.+n(n+1) =n(n+1)(n+2). 3

(2 2" (2"-1)a - 3 If A = then A" = Éro* +1) = -m(n + 1)(a° +n+2) 4 5 Ertr-1)=,n(n² - 1(3n + 2) 12 Given that y =xe", then d"y = (x +n)e*. dx" 6. 1x2 2x3 3x 4 n(n+1) n+1 n'-n is divisible by 6. E (4r - 3) =m(n+1)X2n² – 1). 10 (1x2)+(2+(3x 4)+.+n(n+1) =n(n+1)(n+2). 3

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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22:37 P p ® 2 If A = 2" (2"-1)a) 3 then A" = Er(r? +1) =- n(n + 1)(n² +n + 2) 5 Ér-1)=n(r – D(3n +2) Fel d" y Given that y =xe", then = (x + n)e*. dx" %3D 1 1x2 2x3 3x 4 n(n+1) n+1 n'-n is divisible by 6. Er (4r - 3) = n(n+ 1(2n² – 1). 10 (1x2) +(29+(3x4) +.+ n(n+1) = n(n+1)(n+2). %3D 11 d" 1 (-2)" n! 12 dx" (2x +1) (2x+1)"1 * 2(5 - J2) 17. 5(V3 - V2) 18. 3
Transcribed Image Text:22:37 P p ® 2 If A = 2" (2"-1)a) 3 then A" = Er(r? +1) =- n(n + 1)(n² +n + 2) 5 Ér-1)=n(r – D(3n +2) Fel d" y Given that y =xe", then = (x + n)e*. dx" %3D 1 1x2 2x3 3x 4 n(n+1) n+1 n'-n is divisible by 6. Er (4r - 3) = n(n+ 1(2n² – 1). 10 (1x2) +(29+(3x4) +.+ n(n+1) = n(n+1)(n+2). %3D 11 d" 1 (-2)" n! 12 dx" (2x +1) (2x+1)"1 * 2(5 - J2) 17. 5(V3 - V2) 18. 3
22:37 P p ® 1 Er(r? +1) =-n(n+1)(n? +n+2) 4 4 5 -1)%D n(n² -1)(3n+2) 12 d"y 9. Given that y = xe", then = (x +n)e*. dx" %3D ... 1x2 2x3 3x4 n(n+1) n+1 n'-n is divisible by 6. Er ar -3) = - m(n+ 1)(2n² - 1) . 10 (1x 2) + (29+(3 x 4)+..+ n(n+1) =n(n+1)(n 11 =-n d" (-2)" n! 12 dx" 2x +1 (2x + 1)* %3D
Transcribed Image Text:22:37 P p ® 1 Er(r? +1) =-n(n+1)(n? +n+2) 4 4 5 -1)%D n(n² -1)(3n+2) 12 d"y 9. Given that y = xe", then = (x +n)e*. dx" %3D ... 1x2 2x3 3x4 n(n+1) n+1 n'-n is divisible by 6. Er ar -3) = - m(n+ 1)(2n² - 1) . 10 (1x 2) + (29+(3 x 4)+..+ n(n+1) =n(n+1)(n 11 =-n d" (-2)" n! 12 dx" 2x +1 (2x + 1)* %3D
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