(2) = (2) 1 X2 X3 X x ²0) = (0,0,0) ⁰ X 10x₁ - x₂ = 9 -X₁ + 10x₁₂ - 2x₂ = 7 -2x₂ +10x₂=6 (2) I
(2) = (2) 1 X2 X3 X x ²0) = (0,0,0) ⁰ X 10x₁ - x₂ = 9 -X₁ + 10x₁₂ - 2x₂ = 7 -2x₂ +10x₂=6 (2) I
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
numerical analysis question/Calculate the approximate solution of the linear equation system given below, using the Gauss-Seidel method, by taking the initial iteration from the information given in the picture.
Transcribed Image Text:X
(2)
=(x
(2)
(2)
, Х21 X3
0)
T
жтоз (0.0.0).
X -
10х1 -×2=9
-х, +10х2 -2*3 =7
- 2х2 +0х3 = 6
+10%
(2)
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