**Graphing Linear Equations**In this exercise, you are asked to graph the linear equation. The equation provided is:\[ y - 3x = 1 \]**Steps to Solve for $ y $:**1. Start with the equation: $ y - 3x = 1 $2. Solve for $ y $ by isolating it on one side: \[ y = 3x + 1 \]**Plot the Line on the Graph:**Use the table of values to find points on the line. Here are the x-values given and how to calculate corresponding y-values:- For $ x = -1 $: \[ y = 3(-1) + 1 = -3 + 1 = -2 \]- For $ x = 0 $: \[ y = 3(0) + 1 = 0 + 1 = 1 \]- For $ x = 1 $: \[ y = 3(1) + 1 = 3 + 1 = 4 \]**Table of Values:**\[\begin{array}{|c|c|}\hlinex & y \\\hline-1 & -2 \\0 & 1 \\1 & 4 \\\hline\end{array}\]**Graph Explanation:**- The graph is a standard Cartesian coordinate plane with x and y axes.- The instructions indicate plotting using the points (-1, -2), (0, 1), and (1, 4) to draw the line representing the equation.- Ensure the line is straight and extends in both directions beyond these points.**Additional Features:**- Buttons like "Undo," "Redo," and "Reset" provide flexibility while graphing.- This exercise is suitable for Grade 8, Chapter 4, Section 4.1 on Graphing Linear Equations, Exercise Question #25.

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Answered: Graph the linear equation. Line 6 Undo…

Graph the linear equation. Line 6 Undo A Redo x Reset Grade 8: MRL>Chapter 4>Section 4,1: Graphing Linear Equations>Exercises: 1-33> Question #25 interms ve for y. y- 3%. = 1 -1 1. -p-

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

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Question

**Graphing Linear Equations**

In this exercise, you are asked to graph the linear equation. The equation provided is:

\[ y - 3x = 1 \]

**Steps to Solve for $ y $:**

1. Start with the equation: $ y - 3x = 1 $

2. Solve for $ y $ by isolating it on one side:
\[ y = 3x + 1 \]

**Plot the Line on the Graph:**

Use the table of values to find points on the line. Here are the x-values given and how to calculate corresponding y-values:

- For $ x = -1 $:
\[ y = 3(-1) + 1 = -3 + 1 = -2 \]

- For $ x = 0 $:
\[ y = 3(0) + 1 = 0 + 1 = 1 \]

- For $ x = 1 $:
\[ y = 3(1) + 1 = 3 + 1 = 4 \]

**Table of Values:**

\[
\begin{array}{|c|c|}
\hline
x & y \\
\hline
-1 & -2 \\
0 & 1 \\
1 & 4 \\
\hline
\end{array}
\]

**Graph Explanation:**

- The graph is a standard Cartesian coordinate plane with x and y axes.
- The instructions indicate plotting using the points (-1, -2), (0, 1), and (1, 4) to draw the line representing the equation.
- Ensure the line is straight and extends in both directions beyond these points.

**Additional Features:**

- Buttons like "Undo," "Redo," and "Reset" provide flexibility while graphing.
- This exercise is suitable for Grade 8, Chapter 4, Section 4.1 on Graphing Linear Equations, Exercise Question #25.

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