Solve the area of the following sides 1ocm =- 1mL,:2363cm= 236.3 mら67m- .7ng=223cm= 22.3mL5=221 cam= 22.1m4.om42° 1295 cn=129.5mLo: 67 cm - 6.7mL7= 355 cam= 35.5m: 1293 cm = 129.3 mL= E61cn= 56.1mH0= 301 cne 30.1mLq: 2556 cm = 255. bmTOTAL = 934.2 m

Answered: Image /qna-images/answer/a12d115d-3638-4db3-b965-ee258ee1c66e.jpg

Answered: 1ocm = 1m L,= 2363 cm= 236. 3 m Lo67m-…

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter30: Customary And Metric Steel Rules

Section: Chapter Questions

Problem 3A

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1ocm = 1m L,= 2363 cm= 236. 3 m Lo67m- 6.7m g=223cm= 22.3m 5=221 cm² 22.1m L4: 40cm - 4.0m 42° 1295 cn=129.5m L: 67 cm - 6.7 m Ly= 355 cam = 35.5m Le: 1293 cm= 129.3 m La: 2556 cm = 255.6m L10. 301 cn: so.1m TOTAL = 934.2 m