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1[n] 2[n] = = −2 · 8[n + 1] + @ ծ[n] + 8[n – 1] + 2 = 8[n — 2] . . 8[ո] — 8[n — 1]. (1) (2)

1[n] 2[n] = = −2 · 8[n + 1] + @ ծ[n] + 8[n – 1] + 2 = 8[n — 2] . . 8[ո] — 8[n — 1]. (1) (2)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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a) ha[n] h1[n] *h2[n] b) hb[n] h1 [n] + h2[n] c) Is h1 [n], h2[n], ha[n], hb[n] causal or not? d) If the signal x[n] 2\delta [nj +\delta [n-1] is the input signal in a) (which has the impulse response ha[n]), what is the output signal y[n]? = www.com
Transcribed Image Text:a) ha[n] h1[n] *h2[n] b) hb[n] h1 [n] + h2[n] c) Is h1 [n], h2[n], ha[n], hb[n] causal or not? d) If the signal x[n] 2\delta [nj +\delta [n-1] is the input signal in a) (which has the impulse response ha[n]), what is the output signal y[n]? = www.com
h₁ [n] h₂[n] = = −2 · d[n + 1] + ½ · 6[n] + 5[n − 1] + 2 · d[n − 2] S[n] [n - 12/25 1]. (1) (2)
Transcribed Image Text:h₁ [n] h₂[n] = = −2 · d[n + 1] + ½ · 6[n] + 5[n − 1] + 2 · d[n − 2] S[n] [n - 12/25 1]. (1) (2)
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