What is the value of reverse recovery charge developed in diode having the rate of fall of diode current 40.5 A/µs and Ir is equal to 29 A ? a. 20.77 µC O b. 31.15 µC O c. 4.15 µC O d. 10.38 µC

Electric Motor Control
10th Edition
ISBN:9781133702818
Author:Herman
Publisher:Herman
Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
Problem 12SQ: How is a solid-state diode tested? Explain.
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What is the value of reverse recovery charge developed in diode having the
rate of fall of diode current 40.5 A/µs and Ir is equal to 29 A ?
O a. 20.77 µC
O b. 31.15 µC
O c. 4.15 µC
O d. 10.38 µC
Transcribed Image Text:What is the value of reverse recovery charge developed in diode having the rate of fall of diode current 40.5 A/µs and Ir is equal to 29 A ? O a. 20.77 µC O b. 31.15 µC O c. 4.15 µC O d. 10.38 µC
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