1M 3- 3-2. Mass Transfer from a Pipe Wall. Pure water at 26.1°C is flowing at a velocity of 0.0305 m/s ina tube having an inside diameter of 6.35 mm. The tube is 1.829 m long with the last 1.22 m having the walls coated with benzoic acid. Assuming that the velocity profile is fully developed, calculate the average concentration of benzoic acid at the outlet. Use the physical property data from Example 21.3-2. [Hint: First, calculate the Reynolds number Duplu. Then, calculate NReNse(D/L) (T/4), which is the same as WIDABPL. Ans. (CA-CAO)/(CAi-CAO) = 0.0744, cA 2.193 x 103 kg mol/m .3 .3 1.3- represented within +30 % by Jp Sm JD0.036N2 mental data for liquids are correlated within about +40% by the f -50000 (L2): Re,L -0.5 Using Eq. (21.3-29), 0.00758 0.99(1.700 x 10 Jp 0.99N05 JD0.99N0.5 Re,L Re.L The definition of Jp from Eq. (21.3-5) is ke(Ne (21.3-5) MPLE 21.3-2. Mass Transfer from a Flat Plate e volume of pure water at 26.1°C is flowing parallel to a flat plate Solving for ke k= Jpv(Nc)2. Substituting known values and solving, ic acid, where L 0.244 m in the direction of flow. The water vel m/s. The solubility of benzoic acid in water is 0.02948 kg mol/m2. 5.85 x 10-6 m S -2/3 k0.00758 0.0610 S y of benzoic acid is 1.245 x 10 m2/s. Calculate the mass-transfer In this case, diffusion is for A through nondiffusing B, so k, in Eq. (21.1-10) and the flux NA on: Since the solution is quite dilute, the physical properties of w from Appendix A.2 can be used: should be used: (e-CA)= k (eA-C2) Х вм (21.1-10) A Cubp 8.71 x 10 Pa s 1.0 and keke Also, cA1 = 2.948 x 10-2 ks 0 (large volume of fresh water). Substituting into Since the solution is very dilute, XBM mol/m3 (solubility) and CA2 Eq. (21.1-10), P 996 kg m3 kgmol т 2.948 x 10 0 NA k.(CAI-CA2) = |5.85 x 10-6 m3 m2 DAR 1.245 x 10 S -9 1.726 x 10-7 kgmol S.m2 hmidt number is 8.71 x 10 Pa s No 702 Sc kg 996 m3 pD d mte m2 AB 1.245 x 10-9 Mass transfer for flow past single spheres. For flow past single spheres and for v = D,uplu, where v is the average velocity in the empty test section before the sph rwood number, which is k'D,/DAB, should approach a value of 2.0. This can be Eq. (19.1-24), which was derived for a stagnant medium. Rewriting Eq. (19.-24. ,where Dp is the sphere diameter, ynolds number is kg (0.244m 0.0610 Lup 996 m2 1.700 x 10 2D AB NA CA-CA)= k(CA- CA2) 8.71x 10 Pa -s Re mass-transfer coefficient ke, which is k' for a dilute solution, is then 2D АВ DP Irranging, ort Processes: Momentum, Heat, and Mass P N 2.0 D АВ Sh ourse, natural convection effects could increase k..

1M 3- 3-2. Mass Transfer from a Pipe Wall. Pure water at 26.1°C is flowing at a velocity of 0.0305 m/s ina tube having an inside diameter of 6.35 mm. The tube is 1.829 m long with the last 1.22 m having the walls coated with benzoic acid. Assuming that the velocity profile is fully developed, calculate the average concentration of benzoic acid at the outlet. Use the physical property data from Example 21.3-2. [Hint: First, calculate the Reynolds number Duplu. Then, calculate NReNse(D/L) (T/4), which is the same as WIDABPL. Ans. (CA-CAO)/(CAi-CAO) = 0.0744, cA 2.193 x 103 kg mol/m .3 .3 1.3- represented within +30 % by Jp Sm JD0.036N2 mental data for liquids are correlated within about +40% by the f -50000 (L2): Re,L -0.5 Using Eq. (21.3-29), 0.00758 0.99(1.700 x 10 Jp 0.99N05 JD0.99N0.5 Re,L Re.L The definition of Jp from Eq. (21.3-5) is ke(Ne (21.3-5) MPLE 21.3-2. Mass Transfer from a Flat Plate e volume of pure water at 26.1°C is flowing parallel to a flat plate Solving for ke k= Jpv(Nc)2. Substituting known values and solving, ic acid, where L 0.244 m in the direction of flow. The water vel m/s. The solubility of benzoic acid in water is 0.02948 kg mol/m2. 5.85 x 10-6 m S -2/3 k0.00758 0.0610 S y of benzoic acid is 1.245 x 10 m2/s. Calculate the mass-transfer In this case, diffusion is for A through nondiffusing B, so k, in Eq. (21.1-10) and the flux NA on: Since the solution is quite dilute, the physical properties of w from Appendix A.2 can be used: should be used: (e-CA)= k (eA-C2) Х вм (21.1-10) A Cubp 8.71 x 10 Pa s 1.0 and keke Also, cA1 = 2.948 x 10-2 ks 0 (large volume of fresh water). Substituting into Since the solution is very dilute, XBM mol/m3 (solubility) and CA2 Eq. (21.1-10), P 996 kg m3 kgmol т 2.948 x 10 0 NA k.(CAI-CA2) = |5.85 x 10-6 m3 m2 DAR 1.245 x 10 S -9 1.726 x 10-7 kgmol S.m2 hmidt number is 8.71 x 10 Pa s No 702 Sc kg 996 m3 pD d mte m2 AB 1.245 x 10-9 Mass transfer for flow past single spheres. For flow past single spheres and for v = D,uplu, where v is the average velocity in the empty test section before the sph rwood number, which is k'D,/DAB, should approach a value of 2.0. This can be Eq. (19.1-24), which was derived for a stagnant medium. Rewriting Eq. (19.-24. ,where Dp is the sphere diameter, ynolds number is kg (0.244m 0.0610 Lup 996 m2 1.700 x 10 2D AB NA CA-CA)= k(CA- CA2) 8.71x 10 Pa -s Re mass-transfer coefficient ke, which is k' for a dilute solution, is then 2D АВ DP Irranging, ort Processes: Momentum, Heat, and Mass P N 2.0 D АВ Sh ourse, natural convection effects could increase k..

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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Transcribed Image Text:1M 3- 3-2. Mass Transfer from a Pipe Wall. Pure water at 26.1°C is flowing at a velocity of 0.0305 m/s ina tube having an inside diameter of 6.35 mm. The tube is 1.829 m long with the last 1.22 m having the walls coated with benzoic acid. Assuming that the velocity profile is fully developed, calculate the average concentration of benzoic acid at the outlet. Use the physical property data from Example 21.3-2. [Hint: First, calculate the Reynolds number Duplu. Then, calculate NReNse(D/L) (T/4), which is the same as WIDABPL. Ans. (CA-CAO)/(CAi-CAO) = 0.0744, cA 2.193 x 103 kg mol/m .3 .3 1.3-