1)find c 2)Try to find the cumulative probability function of X 3)find the mean, median,mode and variation of X 4)Try to find P(|X-u|<=1.8o), and compare it
1)find c 2)Try to find the cumulative probability function of X 3)find the mean, median,mode and variation of X 4)Try to find P(|X-u|<=1.8o), and compare it
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
1)find c
2)Try to find the cumulative
3)find the
4)Try to find P(|X-u|<=1.8o), and compare it with the result obtained by the Chebi's theorem. .
Transcribed Image Text:AaBbCcD AaBbCcD AABI AaBb
內文
無間距
標題1
標題
段落
啟用内容
非。四4バソ
16
个付合茂至公理,。
O是。因0Sf(x) <1,且E/()=1.
6.2 若X之機率分配函數為:。
cx x=1,3,5,7
f(x) =
elsewhere
O試求c。O試求X之累加機率函數。。
O試求X之平均數、中位數、眾數、變異數。
の試求P(X-pK1.80),並與生比氏定理所得的結果做比較。
1
OEf(x)=c+3c +5c+7c = 16c =1→c==
16
10
3
50
7
Ax)•
F(X)- 1/16.
1/16e
3/16.
5/16
9/16
7/16
4/16
1e
OLx= 5.25,中位數= 5,眾數-7.。
I
1
E(x³)=
3
--1+
16
25+
49 = 31=03=31 – 5.25 = 3.4375
16
16
16
P(X-Hx $1.80x)=P( X – 5.25|<3.34) = P(5.25– 3.34< X <5.25+3.34)
= P(X = 3) + P(X = 5) + P(X =7)=0.9375,
%3D
Transcribed Image Text:First pic:According to Chai's theorem, P(1X-uaS
1.8 ox)2 >=0.691 can be obtained, which is an
estimate of the lower bound of the actual
probability, which is very different from the
actual probability distribution.
F(x): {cx x=1,3,57 |0 = elsewhere}
This picture is the answer. Please explain how
did they got the answer
OEf(x)=c+3c +5c+7c=16c =1=c==
16
Xo
1e
3
3/16
4/16
5e
7
Ax)•
F(X)-
1/16e
5/16.
7/16
1/16.
9/16
1e
®Hx = 5.25 , $L= 5 , 7 .
I.
1
3
-1+-
16
5
7.
E(x)=
9+
49 = 31=ox= 31–525² = 34375
16
25+
16
16
P(X-Hx $1.80x)= P( X – 5.25|S 3.34) = P(5.25–3.34< X <5.25+3.34) «
= P(X= 3) +P(X = 5) + P(X =7)=0.9375.
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