1C. Write the mechanism for the reaction of 2-Methyl-1-phenyl-2-propanol with HBr.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Mechanism of Reaction: 2-Methyl-1-phenyl-2-propanol with HBr**

**Question:**
1C. Write the mechanism for the reaction of 2-Methyl-1-phenyl-2-propanol with HBr.

**Explanation:**
To address this question, we need to understand the mechanism by which 2-Methyl-1-phenyl-2-propanol reacts with hydrogen bromide (HBr). This type of reaction typically involves the formation of an alkyl halide through a substitution mechanism, often following an SN1 or SN2 pathway depending on the conditions and the structure of the alcohol.

**Steps of the Reaction Mechanism:**
1. **Protonation of the Alcohol Group:**
   - The hydroxyl group (-OH) of 2-Methyl-1-phenyl-2-propanol is protonated by HBr, forming water as a leaving group.
   - Structure: 
     ![Structure of 2-Methyl-1-phenyl-2-propanol]

2. **Formation of the Carbocation:**
   - The water molecule, being a good leaving group, departs, resulting in the formation of a carbocation intermediate at the oxygen's original position.
   - Structure: 
     ![Carbocation Formation]

3. **Nucleophilic Attack:**
   - The bromide ion (Br-) formed from the dissociation of HBr attacks the carbocation, leading to the formation of the final product, 2-Methyl-1-phenyl-2-propyl bromide.
   - Structure: 
     ![Nucleophilic Attack]

This reaction mechanism typically follows the SN1 pathway due to the stability of the carbocation formed as an intermediate step.

**Diagram Explanation:**
The diagrams illustrate the step-by-step progression of the reaction, depicting how the reactant 2-Methyl-1-phenyl-2-propanol converts to the intermediate carbocation and finally to the product 2-Methyl-1-phenyl-2-propyl bromide with the assistance of HBr.

---
Please note that the detailed structures of the intermediates and final product have been described to help learners grasp the transformation at each stage of the reaction.
Transcribed Image Text:**Mechanism of Reaction: 2-Methyl-1-phenyl-2-propanol with HBr** **Question:** 1C. Write the mechanism for the reaction of 2-Methyl-1-phenyl-2-propanol with HBr. **Explanation:** To address this question, we need to understand the mechanism by which 2-Methyl-1-phenyl-2-propanol reacts with hydrogen bromide (HBr). This type of reaction typically involves the formation of an alkyl halide through a substitution mechanism, often following an SN1 or SN2 pathway depending on the conditions and the structure of the alcohol. **Steps of the Reaction Mechanism:** 1. **Protonation of the Alcohol Group:** - The hydroxyl group (-OH) of 2-Methyl-1-phenyl-2-propanol is protonated by HBr, forming water as a leaving group. - Structure: ![Structure of 2-Methyl-1-phenyl-2-propanol] 2. **Formation of the Carbocation:** - The water molecule, being a good leaving group, departs, resulting in the formation of a carbocation intermediate at the oxygen's original position. - Structure: ![Carbocation Formation] 3. **Nucleophilic Attack:** - The bromide ion (Br-) formed from the dissociation of HBr attacks the carbocation, leading to the formation of the final product, 2-Methyl-1-phenyl-2-propyl bromide. - Structure: ![Nucleophilic Attack] This reaction mechanism typically follows the SN1 pathway due to the stability of the carbocation formed as an intermediate step. **Diagram Explanation:** The diagrams illustrate the step-by-step progression of the reaction, depicting how the reactant 2-Methyl-1-phenyl-2-propanol converts to the intermediate carbocation and finally to the product 2-Methyl-1-phenyl-2-propyl bromide with the assistance of HBr. --- Please note that the detailed structures of the intermediates and final product have been described to help learners grasp the transformation at each stage of the reaction.
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