Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
14-19 can you let me know if they are correct, if not what’s the correct answer
![14.
4² +5² = √41
16+25=141
20² = 12².
-400-144=√256
Multi-Step Tell If the measures can be the side lengths of a triangle.
If so, classify the triangle as acute, obtuse, or right.
11. 7, 10, 12
Acute
12. 9, 11, 15 obtuse
72² +10² = 12²
9²+11²=15²
49+100=144
81+121=225
199=119
Solve for the variables. Give you answers in simplest radical from.
9√3
17.
X
60°
□
y
913
24
18√3
30°
NO
y
1213
X
12
15.
+x²
arz
18.
30°
60°
10
X
915
y
5
513
9
2√5
2²+4² = x²
1716=20
13.
9, 40, 41
22
9+40=41²
16.
9.12
5
19.
45
Acute
11
45
5
45°
b
194-81-763
va va
3√7
12
G
652
12.12
12 √2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b2718fa-2d45-4c6e-acf1-628dfb5e33ec%2F723b4e61-4675-434c-b948-4caa49adc7c5%2F09bgm2p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:14.
4² +5² = √41
16+25=141
20² = 12².
-400-144=√256
Multi-Step Tell If the measures can be the side lengths of a triangle.
If so, classify the triangle as acute, obtuse, or right.
11. 7, 10, 12
Acute
12. 9, 11, 15 obtuse
72² +10² = 12²
9²+11²=15²
49+100=144
81+121=225
199=119
Solve for the variables. Give you answers in simplest radical from.
9√3
17.
X
60°
□
y
913
24
18√3
30°
NO
y
1213
X
12
15.
+x²
arz
18.
30°
60°
10
X
915
y
5
513
9
2√5
2²+4² = x²
1716=20
13.
9, 40, 41
22
9+40=41²
16.
9.12
5
19.
45
Acute
11
45
5
45°
b
194-81-763
va va
3√7
12
G
652
12.12
12 √2
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