199=119 Solve for the variables. Give you answers in simplest radical from. 10 14. 913 X 60° 18√3 913 15. X 30° y 5 513 16. 5 45 11 45 V 5

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
Question
14-19 can you let me know if they are correct, if not what’s the correct answer
14.
4² +5² = √41
16+25=141
20² = 12².
-400-144=√256
Multi-Step Tell If the measures can be the side lengths of a triangle.
If so, classify the triangle as acute, obtuse, or right.
11. 7, 10, 12
Acute
12. 9, 11, 15 obtuse
72² +10² = 12²
9²+11²=15²
49+100=144
81+121=225
199=119
Solve for the variables. Give you answers in simplest radical from.
9√3
17.
X
60°
□
y
913
24
18√3
30°
NO
y
1213
X
12
15.
+x²
arz
18.
30°
60°
10
X
915
y
5
513
9
2√5
2²+4² = x²
1716=20
13.
9, 40, 41
22
9+40=41²
16.
9.12
5
19.
45
Acute
11
45
5
45°
b
194-81-763
va va
3√7
12
G
652
12.12
12 √2
Transcribed Image Text:14. 4² +5² = √41 16+25=141 20² = 12². -400-144=√256 Multi-Step Tell If the measures can be the side lengths of a triangle. If so, classify the triangle as acute, obtuse, or right. 11. 7, 10, 12 Acute 12. 9, 11, 15 obtuse 72² +10² = 12² 9²+11²=15² 49+100=144 81+121=225 199=119 Solve for the variables. Give you answers in simplest radical from. 9√3 17. X 60° □ y 913 24 18√3 30° NO y 1213 X 12 15. +x² arz 18. 30° 60° 10 X 915 y 5 513 9 2√5 2²+4² = x² 1716=20 13. 9, 40, 41 22 9+40=41² 16. 9.12 5 19. 45 Acute 11 45 5 45° b 194-81-763 va va 3√7 12 G 652 12.12 12 √2
Expert Solution
steps

Step by step

Solved in 3 steps with 3 images

Blurred answer