19336x 4. 4x – 3y =1 for y 4x=1134 x= 32 width 5. 6x - 3y = 4 for x 6. A = P(1 +rt) for t Set up an equation and solve. 7. A rectangular field is three times as long as it is wide. If the perimeter of the field is 400 yards, what are the field's dimensions? P=1+2w 400= 211aw-3 -21 400 2113(2) -21 379= 2w3 %3D 400-2146 400-27 400 40 -3 376= 2w W=186 A sailboat has a triangular sail with an area of 42 square feet and a base that measures 14 feet. Find the height of the sail. 8.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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I need help setting up the problem of the two questions
146 =6x -2
%3D
4. 4x – 3y = 1 for y
4x=1134
x= 32 width
- 3y = 4 for x
5. 6x -
6. A = P(1+rt) for t
Set up an equation and solve.
7. A rectangular field is three times as long as it is wide. If the
perimeter of the field is 400 yards, what are the field's
dimensions? P=+2w
400= 211aw-3
-21
-21
379=2w3
400-2116
400-27
405 40
-3
376= 2w
W=186
8. A sailboat has a triangular sail with an area of 42 square feet
and a base that measures 14 feet. Find the height of the sail.
Transcribed Image Text:146 =6x -2 %3D 4. 4x – 3y = 1 for y 4x=1134 x= 32 width - 3y = 4 for x 5. 6x - 6. A = P(1+rt) for t Set up an equation and solve. 7. A rectangular field is three times as long as it is wide. If the perimeter of the field is 400 yards, what are the field's dimensions? P=+2w 400= 211aw-3 -21 -21 379=2w3 400-2116 400-27 405 40 -3 376= 2w W=186 8. A sailboat has a triangular sail with an area of 42 square feet and a base that measures 14 feet. Find the height of the sail.
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