19. Suppose that the normal unit vector N of a surface S at z = f(x, y) is determined, how does the denominator upon solving for the normal vector get cancelled out? A. dS = dA B. ds = √x² + y² dA C. D. dS = dS = 1 ()2 + (f) + + 1 dA

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ISBN:9780470458365
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Chapter2: Second-order Linear Odes
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Help me choose the correct answer/s (meaning, there coule be more than one answer) And if the answer is none, choose letter E. If possible, please explain why. Thanks!

19. Suppose that the normal unit vector N of a surface S at z = f(x,y) is determined, how does the denominator upon solving
for the normal vector get cancelled out?
A. ds = dA
В. dS 3
x2 + y² dA
J² + (f,)° + 1 dA
С.
dS =
D. dS = 1
20. Stoke's Theorem
A. cannot be used as a substitute to find the line integral.
B. will require the determination of a normal unit vector.
as a line integral can be solved using its differential form.
D. can be regarded both as a surface integral and line integral.
С.
Transcribed Image Text:19. Suppose that the normal unit vector N of a surface S at z = f(x,y) is determined, how does the denominator upon solving for the normal vector get cancelled out? A. ds = dA В. dS 3 x2 + y² dA J² + (f,)° + 1 dA С. dS = D. dS = 1 20. Stoke's Theorem A. cannot be used as a substitute to find the line integral. B. will require the determination of a normal unit vector. as a line integral can be solved using its differential form. D. can be regarded both as a surface integral and line integral. С.
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