19) Find [sin( x9+ 9x) ]' = _by Chain Rule A) 9x8sin ( x9+ 9x) C) 9(x8+1) cos x 19) B) -9 x sin ( x9+ 9x) D) 9(x8+1)cos ( x9+ 9x) 20) Find the 3rd-order- derivative of y = f(x) = In x, =y= (In x )'''= Exp C) + 6 x-3 20) A) +2 x-3 B) - x- 2 D) - 3x-3 21) Find the 2019th-order- derivative of y = f(x) = ln x at x = 1, d2019y dx2019 21) Ix =1= f(2019) (1)= (ln x )(2019) |x=1=_ A) 2018! B) -2018! C) - 2019! D) 2019!

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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19) Find [sin( x9+ 9x) ]' = _by Chain Rule
A) 9x8sin ( x9+ 9x)
C) 9(x8+1) cos x
19)
B) -9 x sin ( x9+ 9x)
D) 9(x8+1)cos ( x9+ 9x)
d3y
dx3
C) + 6 x-3
20) Find the 3rd-order- derivative of y = f(x) = In x,
=y''' (In x )'' ':
20)
A) +2 x-3
B) - x- 2
D) - 3x-3
21) Find the 2019th-order- derivative of y = f(x) = ln x at x = 1,
d2019y
dx2019
21)
lx=1= f(2019) (1)= (ln x )(2019) |x=1=_
A) 2018!
B) -2018!
C) - 2019!
D) 2019!
Transcribed Image Text:19) Find [sin( x9+ 9x) ]' = _by Chain Rule A) 9x8sin ( x9+ 9x) C) 9(x8+1) cos x 19) B) -9 x sin ( x9+ 9x) D) 9(x8+1)cos ( x9+ 9x) d3y dx3 C) + 6 x-3 20) Find the 3rd-order- derivative of y = f(x) = In x, =y''' (In x )'' ': 20) A) +2 x-3 B) - x- 2 D) - 3x-3 21) Find the 2019th-order- derivative of y = f(x) = ln x at x = 1, d2019y dx2019 21) lx=1= f(2019) (1)= (ln x )(2019) |x=1=_ A) 2018! B) -2018! C) - 2019! D) 2019!
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