187 families have health insurance out of a random sample of 292 families. Kaiser states that the proportion of families who have health insurance is 63%. Can it be concluded that the proportion of families who have health insurance is greater than 63% based on a-level of 0.04? c) To find our Critical Value(s) (CV), will we use invNorm(), invT()?invNorm()d) Please explain the reason for the correct answer for step c.This is a hypotheses test for population proportion (p).Round to Two Decimal PlacesCV =-1.75Enter an integer or decimal number [more..]f) What formula will we use for the test value?Oz(ã1 – 52) – (41 – 42)Ot=+nin2(ê1 – P2) – (pi – p2)Oz =p – pO z =V nOt=

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Description: 187 families have health insurance out of a random sample of 292 families. Kaiser states that the proportion of families who have health insurance is 63%. Can it be concluded that the proportion of families who have health insurance is greater than 6

(c) To find the critical value use invNorm(). (d) From the information, the hypotheses test for…

Answered: 187 families have health insurance out…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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187 families have health insurance out of a random sample of 292 families. Kaiser states that the proportion of families who have health insurance is 63%. Can it be concluded that the proportion of families who have health insurance is greater than 63% based on a-level of 0.04?

c) To find our Critical Value(s) (CV), will we use invNorm(), invT()?
invNorm()
d) Please explain the reason for the correct answer for step c.
This is a hypotheses test for population proportion (p).
Round to Two Decimal Places
CV =-1.75
Enter an integer or decimal number [more..]
f) What formula will we use for the test value?
Oz
(ã1 – 52) – (41 – 42)
Ot=
+
ni
n2
(ê1 – P2) – (pi – p2)
Oz =
p – p
O z =
V n
Ot=

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