18.7 The drawing shows two situations in which charges are placed on the x and y axes. They are all located at the same distance of 5.90 cm from the origin O. For each of the situations in the drawing, determine the magnitude of the net electric field at the origin. +2.0 μ C -5.0 μC (a) -3.0 μC +4.0 μ.C +1.0 μC +6.0 MC (b) -1.0 μC
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- Two point charges each have a value of 3.0 C and are separated by a distance of 4.0 m. What is the electric field at a point midway between the two charges? Ozero O 9.0x107 N/C O 18 x 107 N/C 4.5 x 107 N/C 4Plastic beads can often carry a small charge and therefore can generate electric fields. Three beads are oriented such that 92 is between 9₁ and 93. The sum of the charge on 9₁ and 92 is 91 +92 = -8.3 μC, and the net charge of the system of all three beads is zero. E field lines What charge does each bead carry? μC 91 = 92 = 93 = 000 μC μC9. Four positive point charges are equal in magnitude and placed on the corners of a 2.00 m? square as shown in the figure below. Determine the magnitude of the net force acting on the point charges. +6.00 µc +6.00 µC 2.00 m +6.00 µC 2.00 m +6.00 µC
- 9. In a certain region of space, a uniform electric field has a magnitude of 4.6 x 104 N/C and points in the positive x direction. Find the magnitude and direction of the force this field exerts on a charge of -9.30 uc. A uniform electric field is established by connecting the plates of a para If the plates are separated by 0.75 cm, wThree charges are placed along the x-axis: q1 = 3.00 µC at X1 = -20.0 cm, q2 = -5.00 µC at x2 = 10.0 cm, and q3 = 6.00 µC at x3 = 25.00 cm. Determine the magnitude of the electric field at the origin. O 4 69x106 N/C O 2 96x106 N/C O 6 04x106 N/C O 4.31x106 N/C3. a. A plate has a charge of 4 µC and a surface area of 0.3 m². 0.02 m - + 0.01 m + + Q1 = -1 μC + G₁=3F + + + + What is the electric field 0.01 m away from the plate? a. How much work is required to move a-1 μC charge from 0.01 to 0.02 m² Q = +4 μC A=0.3 m² Given the following configuration of capacitors G=2F
- 23. Model the dome of a Van de Graaff generator as a uniformly charged spherical shell of radius 0.250 m bearing a charge of +1.50 μC. If an electron undergoes uniform circular motion around the dome and 0.300 m above the surface of the dome, what is the speed of the electron? (A) 4.63×107 m/s (B) 5.11×107 m/s (C) 5.55×107 m/s (D) 6.04×107 m/s (E) 6.56×107 m/s9. Three point-like charges are placed at the corners of an equilateral triangle as shown in the figure. Each side of the triangle has a length of 42.0 cm, and the point (A) is located half way between 9₁ and 92 along the side. Find the magnitude of the electric field at point (A). Let q1 -1.20 µC, 92 = -3.50 µC, and q3 = +4.30 μC. N/C ssf60 ss.co = f60 ssf60 ssf60 ssf60 ssf60 ssi?? 91 €60 A 92 sf60 ssf60 ssf60 ssf60 ssf60/s f60 ssf60 55 09jss bojss-155 09588 098 098 09 os oss (9) f60 ssf60 ssf60 ssf60 ssf6 fons 160 ssf60 ssf60 ssf60 ssf60 ssf6060.0 magnitude direction 0.500 mm (a) Red blood cells often become charged and can be treated as point charges. Healthy red blood cells are negatively charged, but unhealthy cells (due to the presence of a bacteria, for example) can become positively charged. In the figure, three red blood cells are oriented such that they are located on the corners of an equilateral triangle. The red blood cell charges are A = 2.30 pC, B = 7.30 pC, and C= -3.90 pC. Given these charges, what would the magnitude and direction of the electric field be at cell A? (1 pC = 1 x 10-¹2 C.) N/C counterclockwise from the +x-axis.
- The figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 9.85 x 106 C,d= 6.97 x 10-6 m, and r = 0.403 cm. +q+ Number i 9440530.064 N/C or V/m d/2 d/2 -9 UnitsA 4.1 MC point charge is placed on the x-axis at the point X₁ = -22.5m. A second, 2.7-MC point Charge is placed on the x-axis at the point X₂ = 10.3m. What is the x-component of the net electric field (in N/C) at the origin? (Remember that vector components can be positive or negative) N/CCan someone help with this question.