18.00 mL of 0.125 M Sn++ is titrated with 0.100 M Ti²+, according to the reaction: Sn++ Ti2+ Sn²+ + Ti³+ Find: a) Exn [0.522 V] b) the equivalence point volume of Ti²+ [45.00 mL] . What is the reduction potential, Exn, of the solution above when the volume of added Ti²+ is: a) 15.00 mL? [0.163 V]

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4. a. 18.00 mL of 0.125 M Sn++ is titrated with 0.100 M Ti²+, according to the reaction:
Sn+ + Ti²+→→ Sn²+ + Ti³+
Find: a) Erxn [0.522 V]
b) the equivalence point volume of Ti²+
[45.00 mL]
b. What is the reduction potential, Ern, of the solution above when the volume of added Ti²+ is:
a) 15.00 mL?
[0.163 V]
b) 22.50 mL?
c) 45.00 mL?
d) 60.00 mL?
e) 90.00 mL?
[0.154 V]
[-0.020 V]
[-0.0340 V]
[-0.368 V]
Transcribed Image Text:4. a. 18.00 mL of 0.125 M Sn++ is titrated with 0.100 M Ti²+, according to the reaction: Sn+ + Ti²+→→ Sn²+ + Ti³+ Find: a) Erxn [0.522 V] b) the equivalence point volume of Ti²+ [45.00 mL] b. What is the reduction potential, Ern, of the solution above when the volume of added Ti²+ is: a) 15.00 mL? [0.163 V] b) 22.50 mL? c) 45.00 mL? d) 60.00 mL? e) 90.00 mL? [0.154 V] [-0.020 V] [-0.0340 V] [-0.368 V]
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