18. Write equations that use rules about operating with fractions and possibly also properties of arithmetic to show why it is valid to cancel to evaluate the expression 22 3 77 ●

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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---

**18. Write equations that use rules about operating with fractions and possibly also properties of arithmetic to show why it is valid to cancel to evaluate the expression**

\[
\frac{22 \cdot 3}{77}
\]

**as follows:**

\[
\frac{\cancel{2}\,^{22} \cdot 3}{\cancel{7}\,^{77}} = \frac{2 \cdot 3}{7} = \frac{6}{7}
\]

---

**Explanation:**

The problem involves simplifying the fraction \(\frac{22 \cdot 3}{77}\) by canceling common factors in the numerator and denominator.

1. **Factorization**: 
   - The numerator \(22\) is factored as \(2 \cdot 11\).
   - The denominator \(77\) is factored as \(7 \cdot 11\).

2. **Cancellation**: 
   - The common factor of \(11\) is canceled from both the numerator and the denominator.

3. **Resulting Expression**:
   - After canceling, the simplified expression becomes \(\frac{2 \cdot 3}{7} = \frac{6}{7}\).

This method uses the property of fractions where you can cancel common factors, leading to a simplified and equivalent expression.
Transcribed Image Text:Certainly! Here's the transcription of the image for an educational website: --- **18. Write equations that use rules about operating with fractions and possibly also properties of arithmetic to show why it is valid to cancel to evaluate the expression** \[ \frac{22 \cdot 3}{77} \] **as follows:** \[ \frac{\cancel{2}\,^{22} \cdot 3}{\cancel{7}\,^{77}} = \frac{2 \cdot 3}{7} = \frac{6}{7} \] --- **Explanation:** The problem involves simplifying the fraction \(\frac{22 \cdot 3}{77}\) by canceling common factors in the numerator and denominator. 1. **Factorization**: - The numerator \(22\) is factored as \(2 \cdot 11\). - The denominator \(77\) is factored as \(7 \cdot 11\). 2. **Cancellation**: - The common factor of \(11\) is canceled from both the numerator and the denominator. 3. **Resulting Expression**: - After canceling, the simplified expression becomes \(\frac{2 \cdot 3}{7} = \frac{6}{7}\). This method uses the property of fractions where you can cancel common factors, leading to a simplified and equivalent expression.
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