18. Use the chemical equation below to determine how many moles of ammonia (NH) will be produced from 4 moles of nitrogen gas (N,). Assume that there is enough H, for all of the N, to be converted to NH. N2 + 3H22NH3 2 moles O 8 moles 3 moles O 4 moles
18. Use the chemical equation below to determine how many moles of ammonia (NH) will be produced from 4 moles of nitrogen gas (N,). Assume that there is enough H, for all of the N, to be converted to NH. N2 + 3H22NH3 2 moles O 8 moles 3 moles O 4 moles
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Question 18: Determining Moles of Ammonia**
Use the chemical equation below to determine how many moles of ammonia (\(NH_3\)) will be produced from 4 moles of nitrogen gas (\(N_2\)). Assume that there is enough \(H_2\) for all of the \(N_2\) to be converted to \(NH_3\).
\[ N_2 + 3H_2 \rightarrow 2NH_3 \]
- [ ] 2 moles
- [ ] 8 moles
- [ ] 3 moles
- [ ] 4 moles
**Explanation:**
The balanced chemical equation \(N_2 + 3H_2 \rightarrow 2NH_3\) indicates that 1 mole of nitrogen gas (\(N_2\)) reacts with 3 moles of hydrogen gas (\(H_2\)) to produce 2 moles of ammonia (\(NH_3\)). If you start with 4 moles of \(N_2\), the amount of \(NH_3\) produced can be calculated by applying the stoichiometric coefficients from the balanced equation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41246b41-0514-4655-8518-9db0e4990a43%2F6ef905a3-0e82-465a-a984-992e3704e2f9%2Fgzhhd9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 18: Determining Moles of Ammonia**
Use the chemical equation below to determine how many moles of ammonia (\(NH_3\)) will be produced from 4 moles of nitrogen gas (\(N_2\)). Assume that there is enough \(H_2\) for all of the \(N_2\) to be converted to \(NH_3\).
\[ N_2 + 3H_2 \rightarrow 2NH_3 \]
- [ ] 2 moles
- [ ] 8 moles
- [ ] 3 moles
- [ ] 4 moles
**Explanation:**
The balanced chemical equation \(N_2 + 3H_2 \rightarrow 2NH_3\) indicates that 1 mole of nitrogen gas (\(N_2\)) reacts with 3 moles of hydrogen gas (\(H_2\)) to produce 2 moles of ammonia (\(NH_3\)). If you start with 4 moles of \(N_2\), the amount of \(NH_3\) produced can be calculated by applying the stoichiometric coefficients from the balanced equation.
![**Question 20: Mole to Mole Ratio in Combustion of Propane**
Consider the following chemical equation which represents the combustion of propane:
\[ \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \]
What is the mole to mole ratio between oxygen (\(\text{O}_2\)) and carbon dioxide (\(\text{CO}_2\))?
- ○ 3:5
- ○ 1:3
- ○ 5:3
- ○ 5:4
**Explanation:**
In the context of the chemical reaction given, the mole ratio we are interested in involves the reactant oxygen (\(\text{O}_2\)) and the product carbon dioxide (\(\text{CO}_2\)). The balanced equation indicates that 5 moles of oxygen react to produce 3 moles of carbon dioxide. Therefore, the correct mole to mole ratio is 5:3.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F41246b41-0514-4655-8518-9db0e4990a43%2F6ef905a3-0e82-465a-a984-992e3704e2f9%2F7eodwcl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 20: Mole to Mole Ratio in Combustion of Propane**
Consider the following chemical equation which represents the combustion of propane:
\[ \text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O} \]
What is the mole to mole ratio between oxygen (\(\text{O}_2\)) and carbon dioxide (\(\text{CO}_2\))?
- ○ 3:5
- ○ 1:3
- ○ 5:3
- ○ 5:4
**Explanation:**
In the context of the chemical reaction given, the mole ratio we are interested in involves the reactant oxygen (\(\text{O}_2\)) and the product carbon dioxide (\(\text{CO}_2\)). The balanced equation indicates that 5 moles of oxygen react to produce 3 moles of carbon dioxide. Therefore, the correct mole to mole ratio is 5:3.
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