18. The equation for voltage as a function of time (instantaneous voltage) across a 25 N resistor is given by V(t)=10sin(31.4 t). Below is a graph (with no labels) representing this function (what you would see on an oscilloscope). If you print out this sheet, you can use this graph, otherwise draw the graph on your paper as shown. a. Label the "x" axis as time, and the “y" axis as voltage. b. On the voltage axis, make a tick mark where the peak voltage is, on both the positive and negative sides. c. Use the equation to find the value for the peak voltage of this wave. Label your tick marks with that number (make it positive or negative as appropriate.) d. How many volts per box is this graph?
18. The equation for voltage as a function of time (instantaneous voltage) across a 25 N resistor is given by V(t)=10sin(31.4 t). Below is a graph (with no labels) representing this function (what you would see on an oscilloscope). If you print out this sheet, you can use this graph, otherwise draw the graph on your paper as shown. a. Label the "x" axis as time, and the “y" axis as voltage. b. On the voltage axis, make a tick mark where the peak voltage is, on both the positive and negative sides. c. Use the equation to find the value for the peak voltage of this wave. Label your tick marks with that number (make it positive or negative as appropriate.) d. How many volts per box is this graph?
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The equation of the voltage across the 25 resistor is
V(t)=10sin(31.4t) v
The voltage V(t) function is shown graph below
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