The switch has been in the left position for a long time and is moved to the right position at time t 0. Determine the time / when vc-0.0Volts.20 210 2t=04 V (71 µF12 VOA. 6.06 µSOB. 1.54 µSOC 2.88 uSOD. 4.05 uSOE. S.11 us

Given circuit,When switch has been in left position for long time (steady state condition), capacitor behaves as an open circuit and voltage across it is, at t<0, (t=0-) VC(0)=VC(0+)=VC(0-) VC(0)=-4 V When switch is moved to the right position at time, t=∞ VC(∞)=12 V At time t=0 the voltage across capacitor is VC(t) Time constant, τ=RC=10×1×10-6=10-5 Now, VC(t)=VC(∞)+VC(0+)-VC(∞)e-tτVC(t)=12+-4-12e-t10-5VC(t)=12-16e-t10-5 To find the time when VC(t)=0 V 0=12-16e-t×105e-t×105=1216-t×105=-0.288t=0.288×105t=2.88 μsec Hence, option C is correct.

Engineering

Electrical Engineering

The switch has been in the left position for a long time and is moved to the right position at time t-0. Determine the time t when ve-0.0 Volts. 20 2 10 2 t=0 4 V 1 µF 12 V OA 6.06 µS OB. 1.54 us OC288 pS OD 4.05 uS OE S.11 uS

The switch has been in the left position for a long time and is moved to the right position at time t-0. Determine the time t when ve-0.0 Volts. 20 2 10 2 t=0 4 V 1 µF 12 V OA 6.06 µS OB. 1.54 us OC288 pS OD 4.05 uS OE S.11 uS

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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