18. Given 7(t)=< sin t, t,cost > , Find:

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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18h

**Problem 18: Vector Function Analysis**

**Given:**  
The vector function \(\vec{r}(t) = \langle \sin t, t, \cos t \rangle\)

**Task:**  
Determine the relevant properties or solve for the specific requirement of the vector function given in the problem statement.

---

### Explanation:

This problem presents a vector function \(\vec{r}(t)\) in terms of the parameter \(t\), with components including trigonometric functions sine and cosine, as well as a linear component. The vector is expressed in three-dimensional space with the components: \(\sin t\), \(t\), and \(\cos t\).

Key points to consider when solving or analyzing this vector function might include:

1. **Magnitude of the Vector:**  
   Calculate \(|\vec{r}(t)|\) using the formula:
   \[
   |\vec{r}(t)| = \sqrt{(\sin t)^2 + t^2 + (\cos t)^2}
   \]

2. **Direction of the Vector:**  
   Determine the direction by looking at unit vectors or normalizing the vector function.

3. **Curvature and Motion Analysis:**  
   Assess the path described by \(\vec{r}(t)\). Since it includes both linear and trigonometric components, expect a helicoidal or spiral path due to the combination of linear \(t\) with rotational components \(\sin t\) and \(\cos t\).

4. **Differentiation:**  
   Differentiate \(\vec{r}(t)\) to find velocity \(\vec{v}(t)\) and acceleration \(\vec{a}(t)\):
   \[
   \vec{v}(t) = \left\langle \frac{d}{dt}(\sin t), \frac{d}{dt}(t), \frac{d}{dt}(\cos t) \right\rangle
   \]
   \[
   \vec{a}(t) = \frac{d}{dt}\vec{v}(t)
   \]

5. **Graphical Representation (if applicable):**  
   Although not provided in the given image, visualize the motion in three dimensions as a curve demonstrating both periodic (due to trigonometric functions) and linear attributes.

By exploring these elements, users can gain a comprehensive understanding of the properties of vector functions, particularly
Transcribed Image Text:**Problem 18: Vector Function Analysis** **Given:** The vector function \(\vec{r}(t) = \langle \sin t, t, \cos t \rangle\) **Task:** Determine the relevant properties or solve for the specific requirement of the vector function given in the problem statement. --- ### Explanation: This problem presents a vector function \(\vec{r}(t)\) in terms of the parameter \(t\), with components including trigonometric functions sine and cosine, as well as a linear component. The vector is expressed in three-dimensional space with the components: \(\sin t\), \(t\), and \(\cos t\). Key points to consider when solving or analyzing this vector function might include: 1. **Magnitude of the Vector:** Calculate \(|\vec{r}(t)|\) using the formula: \[ |\vec{r}(t)| = \sqrt{(\sin t)^2 + t^2 + (\cos t)^2} \] 2. **Direction of the Vector:** Determine the direction by looking at unit vectors or normalizing the vector function. 3. **Curvature and Motion Analysis:** Assess the path described by \(\vec{r}(t)\). Since it includes both linear and trigonometric components, expect a helicoidal or spiral path due to the combination of linear \(t\) with rotational components \(\sin t\) and \(\cos t\). 4. **Differentiation:** Differentiate \(\vec{r}(t)\) to find velocity \(\vec{v}(t)\) and acceleration \(\vec{a}(t)\): \[ \vec{v}(t) = \left\langle \frac{d}{dt}(\sin t), \frac{d}{dt}(t), \frac{d}{dt}(\cos t) \right\rangle \] \[ \vec{a}(t) = \frac{d}{dt}\vec{v}(t) \] 5. **Graphical Representation (if applicable):** Although not provided in the given image, visualize the motion in three dimensions as a curve demonstrating both periodic (due to trigonometric functions) and linear attributes. By exploring these elements, users can gain a comprehensive understanding of the properties of vector functions, particularly
h. \( \left\| \vec{v}(0) \right\| \)

This notation represents the magnitude or norm of a vector \(\vec{v}(0)\) at time \(t = 0\). In mathematical terms, the double vertical lines \( \left\| \cdot \right\| \) denote the norm of a vector, which is a scalar value representing the vector's length or magnitude. It's commonly used in physics and engineering to assess the size of a vector in various applications.
Transcribed Image Text:h. \( \left\| \vec{v}(0) \right\| \) This notation represents the magnitude or norm of a vector \(\vec{v}(0)\) at time \(t = 0\). In mathematical terms, the double vertical lines \( \left\| \cdot \right\| \) denote the norm of a vector, which is a scalar value representing the vector's length or magnitude. It's commonly used in physics and engineering to assess the size of a vector in various applications.
Expert Solution
Step 1

Given:

r(t)=<sin t, t, cos t>

We have to find V(0):

To get V(t) :

Differentiate r(t) with respect to :

ddtr(t)=<ddt(sin t), ddt(t), ddt (cos t)>       V(t)=<cos t, 1, -sin t>

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