Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Q18
![**Question 18:** After balancing the reaction below, the sum of the coefficients is __________
\[ \text{Al(OH)}_3 + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2\text{O} \]
**Explanation:**
To balance this chemical equation, we need to ensure the number of atoms of each element is the same on both sides of the equation.
1. Start with the aluminum (Al) atoms:
- There is 1 Al atom on both sides, so aluminum is already balanced.
2. Balance the chlorine (Cl) atoms:
- There is 1 Cl atom on the reactant side (HCl) and 3 on the product side (AlCl₃).
- Multiply HCl by 3 to balance Cl: \( \text{3HCl} \).
3. Balance the hydrogen (H) atoms:
- There are now 3 H atoms from \(\text{3HCl}\) and 3 H from \(\text{Al(OH)}_3\), totaling 6 H atoms in the reactants.
- The product \( \text{H}_2\text{O} \) has 2 H atoms, so multiply \(\text{H}_2\text{O}\) by 3 to have 6 H atoms: \( \text{3H}_2\text{O} \).
4. Balance the oxygen (O) atoms:
- \(\text{Al(OH)}_3\) has 3 O atoms and \(\text{3H}_2\text{O}\) has 3 O atoms, so oxygen is balanced.
The balanced equation is:
\[ \text{Al(OH)}_3 + \text{3HCl} \rightarrow \text{AlCl}_3 + \text{3H}_2\text{O} \]
The coefficients are 1, 3, 1, and 3. The sum of these coefficients is \(1 + 3 + 1 + 3 = 8\). Therefore, the sum of the coefficients is 8.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e037f4c-cb65-45a7-9b65-cb6a6aa1e30e%2Fcc472590-a1f7-44a7-a4ef-065fdcdbd9cf%2Fgqetsdw_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 18:** After balancing the reaction below, the sum of the coefficients is __________
\[ \text{Al(OH)}_3 + \text{HCl} \rightarrow \text{AlCl}_3 + \text{H}_2\text{O} \]
**Explanation:**
To balance this chemical equation, we need to ensure the number of atoms of each element is the same on both sides of the equation.
1. Start with the aluminum (Al) atoms:
- There is 1 Al atom on both sides, so aluminum is already balanced.
2. Balance the chlorine (Cl) atoms:
- There is 1 Cl atom on the reactant side (HCl) and 3 on the product side (AlCl₃).
- Multiply HCl by 3 to balance Cl: \( \text{3HCl} \).
3. Balance the hydrogen (H) atoms:
- There are now 3 H atoms from \(\text{3HCl}\) and 3 H from \(\text{Al(OH)}_3\), totaling 6 H atoms in the reactants.
- The product \( \text{H}_2\text{O} \) has 2 H atoms, so multiply \(\text{H}_2\text{O}\) by 3 to have 6 H atoms: \( \text{3H}_2\text{O} \).
4. Balance the oxygen (O) atoms:
- \(\text{Al(OH)}_3\) has 3 O atoms and \(\text{3H}_2\text{O}\) has 3 O atoms, so oxygen is balanced.
The balanced equation is:
\[ \text{Al(OH)}_3 + \text{3HCl} \rightarrow \text{AlCl}_3 + \text{3H}_2\text{O} \]
The coefficients are 1, 3, 1, and 3. The sum of these coefficients is \(1 + 3 + 1 + 3 = 8\). Therefore, the sum of the coefficients is 8.
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