18 V Ip 2 kQ O Vp = 12 V VG 12 V o W VDs Ipss = 8 mA 680 k2 + VGS Vs 110 k2 0.68 kN FIG. 7.86 Problem 14.
18 V Ip 2 kQ O Vp = 12 V VG 12 V o W VDs Ipss = 8 mA 680 k2 + VGS Vs 110 k2 0.68 kN FIG. 7.86 Problem 14.
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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![18 V
Ip
2 kQ
O Vp = 12 V
VG
12 V o W
VDs
Ipss = 8 mA
680 k2
+
VGS
Vs
110 k2
0.68 kN
FIG. 7.86
Problem 14.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89d2ad8c-4cf2-44be-b2de-b62a645ac83e%2Fd5f0c7c2-849c-4714-93ae-c8d78ead8b5c%2Fehwpp1t_processed.png&w=3840&q=75)
Transcribed Image Text:18 V
Ip
2 kQ
O Vp = 12 V
VG
12 V o W
VDs
Ipss = 8 mA
680 k2
+
VGS
Vs
110 k2
0.68 kN
FIG. 7.86
Problem 14.
![14. For the network of Fig. 7.86, Vp = 12 V. Determine:
a. Ip.
b. Vs and Vps-
c. Vg and VGs.
d. Vp.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F89d2ad8c-4cf2-44be-b2de-b62a645ac83e%2Fd5f0c7c2-849c-4714-93ae-c8d78ead8b5c%2Fkn8p4p_processed.png&w=3840&q=75)
Transcribed Image Text:14. For the network of Fig. 7.86, Vp = 12 V. Determine:
a. Ip.
b. Vs and Vps-
c. Vg and VGs.
d. Vp.
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