18 The first ionization potential for O is lower than the first ionization potential for N because: O N has a p3 configuration (half filled degenerate orbitals) N is to the right of O on the periodic table N is below O on the periodic table ionization potentials decrease across a representative period Hund's rule is violated
18 The first ionization potential for O is lower than the first ionization potential for N because: O N has a p3 configuration (half filled degenerate orbitals) N is to the right of O on the periodic table N is below O on the periodic table ionization potentials decrease across a representative period Hund's rule is violated
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:**Question 18:**
The first ionization potential for O is lower than the first ionization potential for N because:
- ⭕ N has a p³ configuration (half-filled degenerate orbitals)
- ⭕ N is to the right of O on the periodic table
- ⭕ N is below O on the periodic table
- ⭕ Ionization potentials decrease across a representative period
- ⭕ Hund's rule is violated
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