18-13. The 20-lb block is moving to the right on ahorizontal plane with a velocity of 4 ft/sec when it isacted upon by the horizontal force F = 2e-t, where Fis in pounds and t in seconds. Determine the velocityof the block after the force acts for 2 sec. The force actsin the constant direction shown in the figure.V₁ = 4 ft/secneOC-BSProb. 18-1345°ne45°ofisFticالكل الأنواعتحويلتعليق بالرسمالحقول المطل.... التوضيحيقم بملءتحرير>9:EV

First, we need to find the acceleration of the block by integrating the force function with respect…

Answered: 18-13. The 20-lb block is moving to the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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The mass B is attached to the arm that rotates in the horizontal planeabout a pin in collar A. A motor in A keeps the angular speed of the arm constant at ˙ θ = 2.4 rad/s. Determine the velocity and acceleration of A as functions of the angle θ. Assume that vA = 0 when θ = 0. Friction and the mass of the rotating arm can be neglected.
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4-The 20-g bullet is fired horizontally at 1400 m/s into the 350-g block resting on a smooth surface. If the bullet becomes embedded in the block, what is the velocity of the block immediately after impact
A simple pendulum of mass m = 10 kg and length r= 1 m is mounted on the flatcar, which has a constant horizontal acceleration a = 1 m/s as shown. If the pendulum is released from rest relative to the flatcar at the position 0 = 0 deg, determine the expression for the tension Tin the supporting light rod for 0 = 45 deg and A = 90 deg.
The spring-mounted 0.89-kg collar A oscillates along the horizontal rod, which is rotating at the constant angular rate θ˙=8.2θ˙=8.2 rad/s. At a certain instant, r is increasing at the rate of 700 mm/s. If the coefficient of kinetic friction between the collar and the rod is 0.63, calculate the friction force F exerted by the rod on the collar at this instant.
15-11. During operation the jack hammer strikes the concrete surface with a force which is indicated in the graph. To achieve this the 2-kg spike S is fired into the surface at 90 m/s. Determine the speed of the spike just after rebounding. F (KN) 1500- 0 0 0.1 0.4 t (ms) S
At the instant shown, link CD rotates with an angular velocity of W = 9.0 rad/s. If it is subjected to a couple moment M= 320 N-m, determine the magnitude of the vertical reaction force developed on pin D. The block has a mass of 50 kg and center of mass at G. Neglect the mass of links AB and CD. (Hint, since the mass of link AB or CD is negligible, the external force or moment acting on it sums up to 0.) Please pay attention: the numbers may change since they are randomized. Your answer must include 1 place after the decimal point, and proper unit. Take g = 9.81 m/s². 0.1 m 0.6 m В А 0.4 m' G 0.4 m D C M Your Answer: Answer units
At the instant θ = 22 degrees, the 61 lb bob is momentarily at rest. Given that R=9.9 ft, answer the following: Determine the speed of the bob when θ = 67 degrees Determine the tension in the cord when θ = 67 degrees
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1- The bucket is hoisted by the rope that warps around a drum wheel. If the angular displacement of the wheel is 9 =(3t2-7t) rad, where t is in seconds, determine the velocity and acceleration of the bucket when t= 5 sec
The 40-kg crate is being hoisted by the motor. If at this instant shown the velocity of point P on the cable is 4 m/s and the speed is increasing at 2 m/s2 * what is the power input supplied to the motor if its efficiency is £ = 0.75? Neglect the mass of pulley and cable Vp ↓P = 4 m/s A Question 1: The 40-kg crate is being hoisted by the motor. If at this instant shown the velocity of point P on the cable is 4 m/s and the speed is increasing at 2 m/s², what is the power input supplied to the motor if its efficiency is = 0.75? Neglect the mass of pulley and cable. (a) 0.649 kW (b) 0.865 kW (c) 1.15 kW (d) 1.53 kW
The 15-kg block is subjected to the force shown. Determine its velocity at s= 4m if v= 6 m/s at s=0. Motion occurs to the right. F= (5.1 s)N

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