„ 17.1. A die was thrown 9000 times and of these 3220 vielded a 3 or 4. Can the die be regarded as unbiased ?
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- For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. How hard is it to reach a businessperson by phone? Let p be the proportion of calls to businesspeople for which the caller reaches the person being called on the first try. (a) If you have no preliminary estimate for p, how many business phone calls should you include in a random sample to be 80% sure that the point estimate p^will be within a distance of 0.03 from p? (Round your answer up to the nearest whole number.) ] phone calls (b) A report states that businesspeople can be reached by a single phone call approximately 16% of the time. Using this (national) estimate for p, answer part (a). (Round your answer up to the nearest whole number.) phone callsPlease help me fastCan you help me with the code for how to do this in R please? 1. The study "Digital Footprints" ([Pew Internet and American Life Project]("Digital Footprints" (Pew Internet and American Life Project)) reported that 47\% of Internet users have searched for information about themselves online. The 47\% figure was based on a random sample of Internet users. Suppose that the sample size was `n = 400`. i) Use this information to estimate the true proportion of Internet users who searched information about themselves using a default 95\% confidence interval. ii) Repeat (i) but instead use a 98\% Confidence Level. Use function `prop.test()`. iii) What is the main difference between the intervals computed in (i) and (ii)? What do you think is the role of the confidence level in determining the precision of the confidence interval estimate?
- 45. The mean value of for 0 <= <} is 1+ 4x² 16 В. Т 8. C. D.For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. What percentage of your campus student body is female? Let p be the proportion of women students on your campus. (a) If no preliminary study is made to estimate p, how large a sample is needed to be 99% sure that a point estimate p^ will be within a distance of 0.07 from p? (Round your answer up to the nearest whole number.) | students (b) A report indicates that approximately 60% of college students are females. Answer part (a) using this estimate for p. (Round your answer up to the nearest whole number.) studentsThe distribution of IQ scores of the population is normally distributed with a mean of 100 and a standard deviation of 15 for a particular data value. Since the population is normally distributed all sampling distributions will also be normally distributed. Find the z-scores for each of the following. Make sure to pay attention to the distribution you should use. Write exact answers as decimals. A single person with an IQ of 121: Z-score = Mean of a sample of 4 IQ's is 121: Z-score = 2.80 Mean of a sample of 9 IQ's is 121: Z-score = 1.40 Mean of a sample of 25 IQ's is 121: Z-score = 4.20 Mean of a sample of 100 IQ's is 121: Z-score = Mean of a sample of 625 IQ's is 121: Z-score = 7.00 14.00 35.00
- Plz do fastThe Credit Risk Department of a major bank estimates the default rate on loans under $10,000 to be 4%. The bank will make 2400 loans that are under $10,000 next month. Find the mean of ^p, where ^p is the proportion of defaults on the 2400 loans under $10,000 to be made next month.מבבממרב מ2 מאc. 15. About 5% of the population has a particular genetic mutation. 500 people are randomly selected. Find the mean and standard deviation for the number of people with the genetic mutation in such groups of 500. Round to 2 decimal places.
- A recent survey of 437 restaurant workers found that 279 had at least one other job. Find the sample proportion of restaurant workers who had at least one other job. Round your result to 3 decimal places. Group of answer choices ?̂=0.606p^=0.606 ?̂=0.651p^=0.651 None of these ?̂=0.638p^=0.638 ?̂=0.627Consider trying to predict the life expectancy of citizens in a country based on the birth rate (per 1000 people) in that country. Here is a scatterplot of the data from a random sample of 50 countries. > ggplot (SampCountries, aes (BirthRate, LifeExpectancy)) + geom_point (color = "darkred")+ labs (title = "Life Expectancy by Birth Rate") + Life Expectancy by Birth Rate 80 - 70 - 10 20 30 40 BirthRate Here is (some of) the R output for the linear model for this data. > LifeBirth.lm summary (LifeBirth. lm) Call: Im (formula = LifeExpectancy BirthRate, data = SampCountries) Residuals: Min 10 Median 30 Маx -7.0592 -2.3047 0.9123 2.5019 5.8358 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 85.26295 1.03301 82.54 BirthRate -0.63291 0.04492 -14.09 Residual standard error: 3.424 on 48 degrees of freedom Multiple R-squared: 0.8053, Adjusted R-squared: 0.8012 F-statistic: 198.5 on 1 and 48 DF, p-value: < 2.2e-16 LifeExpectancythe number of people in the household are 2, 7 and 9. Assume the sample size is n=2 are randomly selected with replacement population of 2,7 & 9. The probability are all 1/9. Can you show me step-by-step on how to get S^2 manually? If you use the formula please input actual numbers. Thx Sample probability S^2 2,2 1/9 _______ 2,7 1/9 _____________ 2,9 1/9 _______________ 7,2 1/9 _______________ 7,7 1/9 ________________ 7,9 1/9 _________________ 9,2 1/9 __________________ 9,7 1/9 _______________ 9,9 1/9 _________________
