17. The balanced half-reaction in which chlorine gas is reduced to the aqueous chloride ion is a how many electron process?

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### Question 17: Understanding Electron Processes in Redox Reactions

**The balanced half-reaction in which chlorine gas is reduced to the aqueous chloride ion is a how many electron process?**

In redox reactions, the transfer of electrons plays a crucial role. Specifically, when chlorine gas (\(Cl_2\)) is reduced to form chloride ions (\(Cl^-\)), it indicates an electron gain. Balancing this half-reaction involves understanding how many electrons are involved in the process.

**Explanation:**
The reduction half-reaction can be expressed as follows:

\[ \text{Cl}_2(g) + 2e^- \rightarrow 2\text{Cl}^-(aq) \]

In this reaction, each chlorine molecule (\(Cl_2\)) gains two electrons to form two chloride ions (\(2\text{Cl}^-\)). Therefore, the balanced reduction process for chlorine gas to chloride ion is a two-electron process.
Transcribed Image Text:### Question 17: Understanding Electron Processes in Redox Reactions **The balanced half-reaction in which chlorine gas is reduced to the aqueous chloride ion is a how many electron process?** In redox reactions, the transfer of electrons plays a crucial role. Specifically, when chlorine gas (\(Cl_2\)) is reduced to form chloride ions (\(Cl^-\)), it indicates an electron gain. Balancing this half-reaction involves understanding how many electrons are involved in the process. **Explanation:** The reduction half-reaction can be expressed as follows: \[ \text{Cl}_2(g) + 2e^- \rightarrow 2\text{Cl}^-(aq) \] In this reaction, each chlorine molecule (\(Cl_2\)) gains two electrons to form two chloride ions (\(2\text{Cl}^-\)). Therefore, the balanced reduction process for chlorine gas to chloride ion is a two-electron process.
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