17. Find the indicated measure. QP is the angle bisector. * Find mzSQR if m2 = 13°. %3D

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
icon
Related questions
Topic Video
Question
please help
### Educational Exercise: Angle Bisectors

**Problem Statement:**
17. Find the indicated measure. QP is the angle bisector.

**Question:**
Find \( m \angle SQR \) if \( m \angle 2 = 13^\circ \).

**Diagram Explanation:**
- The image contains a triangle \( SQR \).
- Point \( P \) is on side \( SR \).
- Line segment \( QP \) is drawn, which bisects \( \angle SQR \) into two angles \( \angle 1 \) and \( \angle 2 \).
- It is given that \( \angle 2 \) is \( 13^\circ \).

**Options:**
- 13 degrees
- 26 degrees
- 23 degrees
- 11 degrees

**Solution Steps:**
1. Since \( QP \) is the angle bisector, it divides \( \angle SQR \) into two equal parts.
2. Given \( \angle 2 = 13^\circ \), \( \angle 1 \) is also \( 13^\circ \).
3. Therefore, \( m \angle SQR = \angle 1 + \angle 2 = 13^\circ + 13^\circ = 26^\circ \).

**Answer:**
- 26 degrees
Transcribed Image Text:### Educational Exercise: Angle Bisectors **Problem Statement:** 17. Find the indicated measure. QP is the angle bisector. **Question:** Find \( m \angle SQR \) if \( m \angle 2 = 13^\circ \). **Diagram Explanation:** - The image contains a triangle \( SQR \). - Point \( P \) is on side \( SR \). - Line segment \( QP \) is drawn, which bisects \( \angle SQR \) into two angles \( \angle 1 \) and \( \angle 2 \). - It is given that \( \angle 2 \) is \( 13^\circ \). **Options:** - 13 degrees - 26 degrees - 23 degrees - 11 degrees **Solution Steps:** 1. Since \( QP \) is the angle bisector, it divides \( \angle SQR \) into two equal parts. 2. Given \( \angle 2 = 13^\circ \), \( \angle 1 \) is also \( 13^\circ \). 3. Therefore, \( m \angle SQR = \angle 1 + \angle 2 = 13^\circ + 13^\circ = 26^\circ \). **Answer:** - 26 degrees
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Research Design Formulation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, geometry and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
Geometry
ISBN:
9781337614085
Author:
Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:
Cengage,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning