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17. a.Calculate the AG°rxn using the following information. 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H₂O(g) -300.1 -228.6 AG°f (kJ/mol) -33.4 AG°rxn = ? b. Solve using H and S values located in appendix. T=296K A) +990.6 kJ B)-495.3 kJ C) +528.7 kJ D) +66.8 kJ E) -990.6 kJ

17. a.Calculate the AG°rxn using the following information. 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H₂O(g) -300.1 -228.6 AG°f (kJ/mol) -33.4 AG°rxn = ? b. Solve using H and S values located in appendix. T=296K A) +990.6 kJ B)-495.3 kJ C) +528.7 kJ D) +66.8 kJ E) -990.6 kJ

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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17. a.Calculate the AG rxn using the following information. 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H2O(g) AG°rxn = ? AG°f (kJ/mol) -33.4 -300.1 -228.6 b. Solve using H and S values located in appendix. T=296K A) +990.6 kJ B)-495.3 kJ C) +528.7 kJ D) +66.8 kJ E) -990.6 kJ 4
Transcribed Image Text:17. a.Calculate the AG rxn using the following information. 2 H2S(g) + 3 O2(g) → 2 SO2(g) + 2 H2O(g) AG°rxn = ? AG°f (kJ/mol) -33.4 -300.1 -228.6 b. Solve using H and S values located in appendix. T=296K A) +990.6 kJ B)-495.3 kJ C) +528.7 kJ D) +66.8 kJ E) -990.6 kJ 4
Expert Solution
Step 1

According to the question we have,

                              ∆G°f H2S= -33.4 KJ∆G°f SO2=-300.1 KJ∆G°f H2O= -228.6 KJ

These are given for the following chemical reaction,

                 2H2Sg+3O2g→ 2SO2g+2H2Og

we have to find the ∆G°rxn for the given reaction.

 

 

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