(1³7). (a) If Q is the point (x, sin(¹37)), find the slope of the secant line PQ (correct to four decimal places) for the following values of x. The point P(1, 0) lies on the curve y = sin( (1) 2 1

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Chapter1: Functions And Models
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The point P(1, 0) lies on the curve y = sin
(a) If Q
is the point (x, sin(¹3¹)), find the slope of the secant line PQ (correct to four decimal places) for the following values of x.
(i) 2
1
(ii) 1.5
(iii) 1.4
(iv) 1.3
(v) 1.2
2.5
(vi) 1.1
(vii) 0.5
0
(viii) 0.6
(ix) 0.7
(x) 0.8
n(13″).
X
X
Transcribed Image Text:The point P(1, 0) lies on the curve y = sin (a) If Q is the point (x, sin(¹3¹)), find the slope of the secant line PQ (correct to four decimal places) for the following values of x. (i) 2 1 (ii) 1.5 (iii) 1.4 (iv) 1.3 (v) 1.2 2.5 (vi) 1.1 (vii) 0.5 0 (viii) 0.6 (ix) 0.7 (x) 0.8 n(13″). X X
(iii) 1.4
(iv) 1.3
(v) 1.2
2.5
(vi) 1.1
(vii) 0.5
0
(viii) 0.6
(ix) 0.7
(x) 0.8
(xi) 0.9
-9.8
X
X
Do the slopes appear to be approaching a limit?
As x approaches 1, the slopes do not appear to be approaching any particular value
Transcribed Image Text:(iii) 1.4 (iv) 1.3 (v) 1.2 2.5 (vi) 1.1 (vii) 0.5 0 (viii) 0.6 (ix) 0.7 (x) 0.8 (xi) 0.9 -9.8 X X Do the slopes appear to be approaching a limit? As x approaches 1, the slopes do not appear to be approaching any particular value
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